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Dmitry [639]
3 years ago
8

For which of the following transitions would a hydrogen atom absorb a photon with the longest wavelength?

Chemistry
1 answer:
Talja [164]3 years ago
5 0

Answer:

Hence among the options a and c, option d is that the correct answer because it has rock bottom energy ( as n value increases, energy decreases as energy levels come closer).

Explanation:

The relation between energy and wavelength is:

\Lambda = hC/E  

From this equation, it's clear that wavelength and energy are inversely proportional to every other. The Lower the energy of a specific transition, the longest will the wavelength be of that specific transition.  

Among the given options, options b and d are often ruled out, since those transitions produce to release of a photon because it is coming down from an excited state.

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What is the noble-gas configuration for As​
jasenka [17]

Answer:

Noble gas Electronic configuration of arsenic:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Explanation:

Arsenic is metalloid.

Its atomic number is 33.

Its atomic mass is 75 amu.

Its symbol is As.

It is usually present in combine with sulfur and metals.

it is used in bronzing.

It is also used for hardening.

Electronic configuration:

As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

Noble gas Electronic configuration:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

Noble gas electronic configuration is shortest electronic configuration by using the noble gas elements full octet electronic configuration.

3 0
3 years ago
Please review the attachment
astra-53 [7]

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

8 0
3 years ago
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Ymorist [56]

Answer:

false

Explanation:

trust

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3 years ago
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2 years ago
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grigory [225]
The answer is D I JUST TOOKM THE TEST
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3 years ago
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