v^2 = v0^2 +2ad
v^2 = 22^2 + 2*3.78*45 = 824.2
v= √824.2 = 28.7 m/s
 
        
             
        
        
        
There are plates under the surface that shift when there is interruption on the surface <span />
        
             
        
        
        
I think the answer would be letter B.
        
             
        
        
        
A gravitational field is the field generated by a massive body, that extends into the entire space. Every object with mass m experiences a force F when immersed in a gravitational field. The intensity of the force is equal to

where 

 is the gravitational  constant, M is the mass of the source of the field (e.g. the mass of a planet), and r is the distance between the object and the source of the field. The force is always attractive. 
A possible way to measure the intensity of a gravitational field is by measuring the acceleration a of the object immersed in this field. In fact, for Newton's second law we have:

but since 

we can write

Therefore, by measuring the acceleration of the object, we also measure the intensity of the field.
 
        
        
        
Answer:
13 m/s
Explanation:
Given:
Δy = 8.2 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (9.8 m/s²) (8.2 m)
v = 12.7 m/s
Rounded to two significant figures, the speed is 13 m/s.