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Oxana [17]
3 years ago
13

A car travels a distance of 540km in 6hours.What speed did he travel at?​

Physics
1 answer:
Sloan [31]3 years ago
5 0

Answer: 90 km/hr

Explanation:

Speed= distance divided by time

540/6

= 90km/hr

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A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh
dem82 [27]

Answer:

Explanation:

a )

Reaction force of the ground

R = mg

= 160 N

Maximum friction force possible

= μ x R

= μ x 160

= .4 x 160

= 64 N .

b )

 160 N will act at middle point . 740N will act at distance of 3 / 5 m from the wall ,

Taking moment about top point of ladder

160 x 1.5 + 740 x 3/5 + f x 4 = 900 x 3

240 + 444 + 4f = 2700

f = 504 N

c )

Let x be the required distance.  

Taking moment about top point of ladder

160 x 1.5 + 740 x 3 x / 5 + .4 x 900 x 4  = 900 x 3  ( .4 x 900 is the maximum friction possible )

240 + 444 x + 1440  = 2700

x = 2.3  m

so man can go upto 2.3 at which maximum friction acts .

8 0
3 years ago
Which of the following is transferred in order for static electricity to occur?
adell [148]
C. is the answer I believe
8 0
3 years ago
Read 2 more answers
Which mixture is most likely to be homogeneous?
BlackZzzverrR [31]
C would be the answer
4 0
2 years ago
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Why is it important for car designers to keep accurate records of their experimental procedures
storchak [24]
Like all experiments, it's important to keep records of the their experiment procedures so future car designers and experimenters can compare and contrast their results from their experiment and improve their experiment accordingly. I'm pretty sure this is it. Stay cool my man.
5 0
3 years ago
Steam flows steadily through an adiabatic turbine. The inlet conditions of the steam are 4 MPa, 500°C, and 80 m/s, and the exit
Delicious77 [7]

Answer:

a)23.4KW

b)12.11MW

c)1.155m^2

Explanation:

Hello!

To solve this problem follow the steps below

1. We will call 1 at the turbine entrance and 2 at the exit.

2. To calculate the change in kinetic energy, calculate the kinetic energy at the entrance and exit of the turbine and find the difference.

E=0.5mV^2

m=mass flow=12kg/s

E=kinetic energy

V=speed

solving

E=(0.5)(12kg/s)(80m/S)^2-(0.5)(12kg/s)(50m/S)^2=23400W=23.4KW

3. We find the enthalpies in states 1 and 2, and the density in the state 2 by thermodynamic tables

note: Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties such as pressure and temperature.  

h1=Enthalpy(Water;T=500C;P=4000kPa)

=3445KJ/kg

h2=Enthalpy(Water;x=0,92(quality);P=30kPa)=2438KJ/kg

density2=0.2078kg/m^3

4.

use the first law of thermodynamics that states that the energy entering the system is the same as the one that must go out, consider the flow energy, the work done and the kinetic energy

mh1+0.5mV1^2=mh2+W+0.5mV2^2\\W=m(h1-h2)+0.5m(V1^2-V2^2)\\W=12(3445000-2438000)+0.5(12)(80^2-50^2)=12107400W=12.11MW

5.

to find the speed at the exit of the turbine we remember that the mass flow is defined as the product between the velocity density and the cross-sectional area

m=(density)(A2)V2

A2=\frac{m}{(density)(V2)} =\frac{12}{(0.2078)(50)}=1.155m^2

7 0
3 years ago
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