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3 years ago

A softball is thrown straight up. To what height will it go if it takes 2.0 sec to reach the highest point?

Physics

1 answer:

Genrish500 [490]3 years ago

6 0

Answer:

4.4 m

Explanation:

Given:

v = 0 m/s

a = -9.8 m/s²

t = 2.0 s

Find: Δy

Δy = vt − ½ at²

Δy = 0 − ½ (-9.8) (2.0)²

Δy = 4.4 m

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Consider a vertical elevator whose cabin has a total mass of 800 kg when fully loaded and 150 kg when empty. The weight of the e

Eddi Din [679]

Answer:

Part a)

$P = 4.71 \times 10^3 Watt$

Part b)

$P = 2.94 \times 10^3 W$

Part c)

$P = 9.4 \times 10^3 W$

Part d)

$P = 3.9 \times 10^3 W$

Explanation:

Part a)

When cabin is fully loaded and it is carried upwards at constant speed

then we will have

net tension force in the rope = mg

$T = (800)(9.81)$

$T = 7848 N$

now it is partially counterbalanced by 400 kg weight

so net extra force required

$F = 7848 - (400 \times 9.81)$

$F = 3924 N$

now power required is given as

$P = Fv$

$P = 3924 (1.2)$

$P = 4.71 \times 10^3 Watt$

Part b)

When empty cabin is descending down with constant speed

so in that case the force balance is given as

$F + (150 \times 9.8) = (400 \times 9.8)$

$F = 2450 N$

now power required is

$P = F.v$

$P = (2450)(1.2)$

$P = 2.94 \times 10^3 W$

Part c)

If no counter weight is used here then for part a)

$F = 7848 N$

now power required is

$P = F.v$

$P = 7848 (1.2)$

$P = 9.4 \times 10^3 W$

Part d)

Now in part b) if friction force of 800 N act in opposite direction

then we have

$F + (150 \times 9.8) = 800 +(400 \times 9.8)$

$F = 3250 N$

now power is

$P = (3250)(1.2)$

$P = 3.9 \times 10^3 W$

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3 years ago

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Which of these circuit schematics has an ammeter? Α. Α B. B C. C D. D

madam [21]

Answer:

d is the correct answer for this question hope it helps

Explanation:

when you see a A in a circle the the ammeter

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Answer:

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TECHNOLOGY A Lamborghini Aventador accelerates from rest to 100 km / h in 2.9 s. The mass of the car is 1575 kg Calculate the po

DerKrebs [107]

At 100 km/hr, the car's kinetic energy is

KE = (1/2) (mass) (speed)²

KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²

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KE = 607,639 Joules

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