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1s to the second power, 2s to the second power, 2p to the 6th power, 3s to the second power and 3p to the third power.
Answer:
"1.4 mL" is the appropriate solution.
Explanation:
According to the question,
Now,
Increase in volume will be:
⇒ ![\Delta V = \alpha\times v_0\times \Delta \epsilon](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Calpha%5Ctimes%20v_0%5Ctimes%20%5CDelta%20%5Cepsilon)
By putting the given values, we get
![=1.12\times 10^{-4}\times 500\times 25](https://tex.z-dn.net/?f=%3D1.12%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20500%5Ctimes%2025)
![=1.12\times 10^{-4}\times 12500](https://tex.z-dn.net/?f=%3D1.12%5Ctimes%2010%5E%7B-4%7D%5Ctimes%2012500)
![=1.4 \ mL](https://tex.z-dn.net/?f=%3D1.4%20%20%5C%20mL)