Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol
Answer: 1 × 10−2 M
Explanation: Kw is known as the constant of water dissociation and its value is found to be . It is the product of the concentration of [H3O+] and [OH -] ions .
Dissociation of water can be represented by -
Kw = [H3O+] [OH -]
As we know that pKw = - log Kw,
Thus pKw = 14
pOH = - log OH- = - log (10^{-12}) = 12
and pKw = pH + pOH
14 = pH + 12
pH = 14 - 12 = 2
pH = -log H3O+
2 = -log H3O+
Therefore, [H3O+] = 1 × 10−2 M
Answer:
im not sure
Explanation:
i went on here looking nobody answered yet
Here, Equation: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
We know, Concentration (c) = Number of moles(n) / Volume (v)
Substitute the given values,
0.02 = n / 0.3 [ 300 mL = 0.3 L ]
n = 0.3 * 0.02
n = 0.006
Now, According to stoichiometry, There is 1 Molecule of Sodium sulfate produces for every 2 molecules of NaOH.
So, Number of Moles of Na₂SO₄ = 0.006/2 = 0.003
Given mass = Molar mass * Number of moles
M = 142.04 * 0.003
M = 0.426 g
In short, Your Answer would be: 0.426 g
Hope this helps!
Neither gasses nor plasma have definite volume, unless they are contained in a specific space. The molecules are spreading out and constantly moving.