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atroni [7]
3 years ago
12

Has anyone done the Physical Science B- Forces and Motion Unit Test?? If so could you please help me

Physics
1 answer:
Sedbober [7]3 years ago
4 0
I haven't, but I'm sure @Porshia has!
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Nonconjugated β,γ-unsaturated ketones are in base-catalyzed equilibrium with their conjugated α,β-unsaturated isomers. The mecha
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Answer:

Explanation:

The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated β, γ- unsaturated ketones, like 3-cyclohexanone to their conjugated α, I²- unsaturated isomers.

Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an α- hydrogen from the protonated 3-cyclo hexanone to yield ethanol

2-cyclo hexanone can be obtained by acid catalyzation of 3-cyclohexanone isomers through the formation of it's "enol".

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3 years ago
All parts of the electromagnetic spectrum travel at a speed of 3 × 108 m/s when traveling through no medium. A "vacuum” means th
il63 [147K]

Answer:

the answer is D.

Explanation:

8 0
3 years ago
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Jorge rides his bicycle to school every morning. The school is 4 km away from Jorge's house and it takes him 30 minutes to ride
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5 0
3 years ago
"A 75 kg swimmer dives horizontally off a 500 kg raft. If the diver's speed immediately after leaving the raft is 4 m/s, what is
svet-max [94.6K]

Answer:

0.6 m/s

Explanation:

Let the raft speed be v.

Given:

Mass of the swimmer (m) = 75 kg

Mass of the raft (M) = 500 kg

Speed of swimmer after leaving the raft (u) = 4 m/s

Now, the given situation can be considered a problem of conservation of total momentum before and after collision.

Momentum is the product of mass and velocity.

Here, the swimmer and raft are the bodies in collision.

So, before the collision, both the bodies were at rest. So, initial momentum is 0. Now, from conservation of momentum, the final momentum of the system must be 0 after the collision. Therefore,

Final Momentum = 0

mu+Mv=0\\\\Mv=-mu\\\\v=-\dfrac{mu}{M}

Plug in the given values and solve for 'v'. This gives,

v=-\frac{75\times 4}{500}\\\\v=-\frac{300}{500}=-0.6\ m/s

The final velocity of the raft is -0.6 m/s. Now, speed is the magnitude of velocity.

Therefore, the corresponding raft speed is 0.6 m/s.

7 0
4 years ago
Calculate the pressure when a force of 200N acts on an area of 0.05cm2<br> .
deff fn [24]

FORCE ACTING ON THE BODY , F = 200N

AREA ON WHICH THE FORCE IS ACTING , A = 0.05 CM²

= 0.05*(10⁻²)

= 0.05*10⁻² M²

TO CONVERT CM TO M * BY 10⁻²

PRESSURE = FORCE / AREA

PRESSURE = 200/0.05*10⁻⁴

= 200*10⁴/0.05

= 200*10⁴*10²/5

= 20*10⁵/5

= 4*10⁵ N/M².

HOPE THIS HELPS.

4 0
2 years ago
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