Has anyone done the Physical Science B- Forces and Motion Unit Test?? If so could you please help me

A sailboat travels a distance of 600 m in 40 seconds. What speed is it going?

Gekata [30.6K]

Answer:

15 miles /seconds

Explanation:

Distance = 600m

Time = 40 seconds

Speed=?

$speed = \frac{distance}{time} \\ speed = \frac{600}{40}$

Simplify

$\frac{600}{40} = \frac{60}{4} \\ = 15$

7 0

3 years ago

A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1

Hoochie [10]

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

$v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h]$

In order to find the vertical component, we must use the sine function of the angle.

$V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h]$

7 0

3 years ago

A particle of mass 4.00 kg is attached to a spring with a force constant of 100 N/m. It is oscillating on a frictionless, horizo

jeka57 [31]

Answer:

a. A = 0.735 m

b. T = 0.73 s

c. ΔE = 120 J decrease

d. The missing energy has turned into interned energy in the completely inelastic collision

Explanation:

a.

4 kg * 10 m /s + 6 kg * 0 m/s = 10 kg* vmax

vmax = 4.0 m/s

¹/₂ * m * v²max = ¹/₂ * k * A²

m * v² = k * A² ⇒ 10 kg * 4 m/s = 100 N/m * A²

A = √1.6 m ² = 1.26 m

At = 2.0 m - 1.26 m = 0.735 m

b.

T = 2π * √m / k ⇒ T = 2π * √4.0 kg / 100 N/m = 1.26 s

T = 2π *√ 10 / 100 *s² = 1.99 s

T = 1.99 s -1.26 s = 0.73 s

c.

E = ¹/₂ * m * v²max =

E₁ = ¹/₂ * 4.0 kg * 10² m/s = 200 J

E₂ = ¹/₂ * 10 * 4² = 80 J

200 J - 80 J = 120 J decrease

d.

The missing energy has turned into interned energy in the completely inelastic collision

3 0

3 years ago

Draw a simple circuit that lights up a bulb.

coldgirl [10]

Hope this helps

Ps- U can pick between these two pictures

Please mark as brainliest

5 0

2 years ago

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What force in Newton is required to accelerate a car starting from rest to 20 m/s in 15 seconds if the mass of the car is 2500 k

Lyrx [107]

We will solve this question using the second law of motion which states that force is directly equal to the product of mass and acceleration.

$\sf \: F=ma$

Where,

F is force
m is mass
a is acceleration

In our case,

F = ?
m = 2500 kg
a = 20m/s

$\tt \: F_{net} = 2500 \times 20 \\ \tt= 50000$

<em>Thus, The force of 50000 Newton is required to accelerate a car of 2500 kg...~</em>

3 0

2 years ago

Read 2 more answers