The time period of the simple pendulum is 2.4 seconds.
Given the data in the question;
- Time taken to swing from leftmost point to rightmost point;
- Period of the pendulum;
<h3>What is Period?</h3>
Period is the time needed for a complete cycle of vibration to pass a given point.
Period of a pendulum is the of time needed for it to complete one full back-and-forth motion. It is the time required to for the pendulum to swing from leftmost point to rightmost point and back to leftmost point.
Now, if it took the pendulum 
to swing from leftmost point to rightmost point, it will also take the pendulum to swing back to its original position( leftmost point )
Hence,
= time taken to swing from leftmost to rightmost + time taken to swing from rightmost point to leftmost point.
Therefore, the time period of the simple pendulum is 2.4 seconds.
Learn more about Time Period: brainly.com/question/27135322
The Battle of the Bulge in the winter of 1944 was the last Great German offensive of the Second World War.
When an object is falling and reaches a constant velocity, the net force on the object is <em>zero</em> (it's not accelerating), and the weight of the object is equal to <em>the force of air resistance against the object</em>. (choice-D)
The height of the roof is <u>3.57m</u>
Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.
Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.
The length of the window s is given by,
The first drop is at the bottom and it takes 5t seconds to reach down.
The height of the roof h is the distance traveled by the first drop and is given by,
the height of the roof is 3.57 m
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