Different between rarer medium and denser medium at least 5 point each?? can anyone help me to solve this question
1 answer:
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Answer:
The phase difference is 0.659 rad.
Explanation:
Given that,
Distance between two identical loudspeakers d= 1.00 m
Distance between speakers and listener r= 4.00 m
Frequency = 300 Hz
Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer
We need to calculate the r'
Using Pythagorean theorem
Where, d = distance between two identical loudspeakers
r = distance between speakers and listener
Put the value into the formula
We need to calculate the path difference
Using formula of path difference
We need to calculate the wavelength
Using formula of wavelength
Where, v = speed of sound
f = frequency
Put the value into the formula
We need to calculate the phase difference
Using formula of phase difference
Hence, The phase difference is 0.659 rad.
Answer:
t = 1.41 sec.
Explanation:
If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.
First, we need to find the value of acceleration, which is the same for both blocks.
If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:
F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)
⇒ a = ( = g/5 m/s²
Once we got the value of a, we can use for instance this kinematic equation, and solve for t:
Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.