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Nana76 [90]
3 years ago
10

Find our the total distance between those 2 womens after 100 seconds. Refer the image for the full question ASAP. Give me a comp

lete brief solution of this above question!​

Physics
1 answer:
diamong [38]3 years ago
3 0
<h3>Given</h3>

\small\bf\red{First\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 15m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

\small\bf\green{Second\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 20m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

<h3>To Find</h3>

\:\:\:\:\bullet\:\:\sf{Distance \: between \:them \:after \:{\sf{\blue{100 \:seconds}}}} \\

<h3>Solution </h3>

\\→\:\:\:\sf Distance\: travelled \:by \:1st \:women\: = \: Velocity \times Time\:taken

→\:\:\:\sf 15 \times 100

→\:\;\:\sf 1500m

→\:\:\:\sf s_{1} = {\sf{\red{1500m}}} \\ \\

\Rightarrow\:\:\:\sf Distance \:travelled \:by\: 2nd \:women\: = \: Velocity \times Time\:taken

\Rightarrow\:\:\:\sf 20 \times 100

\Rightarrow\:\:\:\sf  2000m

\Rightarrow\:\:\:\sf s_{2} = {\sf{\purple{2000m}}} \\ \\

\small{\underline{\bf{Now, \:Distance \:between \:them\: =\: s_{2} - s_{1}}}_{}}

\hookrightarrow\:\:\:\sf 2000 - 1500

\hookrightarrow\:\:\:\bf \pink{500m} \\ \\

{\underline{\bf{Hence, }}}

Total Distance between them after \bf{100 \:seconds} is \bf\orange{500m}

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Explanation:

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4 0
3 years ago
It is easier to see clothes with pointed needle than a blunt one​
topjm [15]

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It is easier to see clothes with pointed needle than a blunt one because pressure exerted is more in a pointed needle as it occupies less space compared to blunt needle, A blunt has more surface area so the pressure exerted will less as compared to a pointed needle.

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3 years ago
Which of the following must be transformed into electrical energy when biomass is used as an energy resource?
dangina [55]
It’s chemical energy





Your welcome :)
3 0
3 years ago
Two soccer players, Mia and Alice, are running as Alice passes the ball to Mia. Mia is running due north with a speed of 5.30 m/
Tju [1.3M]

Answer:

a) v_{p}  = 2.83 m / s ,  b)  50.5º north east

Explanation:

This is a vector problem.

         v_{bg} = v_{bm} + v_{mg}

The speed of the ball with respect to the ground is the speed of the ball with respect to Mia plus the speed of Mia with respect to the ground

To make the sum we decompose the speed of the ball in its components

The angle of 30 east of the south, measured from the positive side of the x axis is

             θ = 30 + 270 = 300

            v_{bx} = v_{b} cos 300

             v_{by} = v_{b} sin. 300

             v_{bx} = 3.60 cos 300 = 1.8 m / s

             v_{by} = 3.60 sin 300 = -3,118 m / s

Let's add speeds on each axis

X axis

            vₓ = v_{bx}

             vₓ = 1.8 m / s

Y Axis  

             v_{y} = v1 - vpy

             v_{y} = 5.30 - 3.118

             v_{y} = 2.182 m / s

The magnitude of the velocity can be found using the Pythagorean theorem

              v_{p} = √ (vₓ² + v_{y}²)

               v_{p} = √ (1.8² + 2.182²)

               v_{p} = 2,829 m / s

               v_{p}  = 2.83 m / s

b) for direction use trigonometry

              tan θ = v_{y} / vₓ

              θ = tan ⁺¹ v_{y} / vₓ

              θ = tan⁻¹ 2.182 / 1.8

         Tea = 50.48º

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8 0
3 years ago
A scuba diver, submerged under water looks up and seessunlight
maw [93]

Answer:

41.7975\ ^{\circ}

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n_2 = Refraction index of water = 1.333

n_1 = Refraction index of air = 1

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From Snell's law we have

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The angle measured from the vertical does the sunlight strike thesurface of the water is 41.7975\ ^{\circ}

5 0
3 years ago
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