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3 years ago

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Find our the total distance between those 2 womens after 100 seconds. Refer the image for the full question ASAP. Give me a comp

lete brief solution of this above question!

1 answer:

diamong [38]3 years ago

3 0

<h3>Given</h3>

$\small\bf\red{First\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 15m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}$

$\small\bf\green{Second\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 20m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}$

<h3>To Find</h3>

$\:\:\:\:\bullet\:\:\sf{Distance \: between \:them \:after \:{\sf{\blue{100 \:seconds}}}} \\$

<h3>Solution </h3>

$\\→\:\:\:\sf Distance\: travelled \:by \:1st \:women\: = \: Velocity \times Time\:taken$

$→\:\:\:\sf 15 \times 100$

$→\:\;\:\sf 1500m$

$→\:\:\:\sf s_{1} = {\sf{\red{1500m}}} \\ \\$

$\Rightarrow\:\:\:\sf Distance \:travelled \:by\: 2nd \:women\: = \: Velocity \times Time\:taken$

$\Rightarrow\:\:\:\sf 20 \times 100$

$\Rightarrow\:\:\:\sf 2000m$

$\Rightarrow\:\:\:\sf s_{2} = {\sf{\purple{2000m}}} \\ \\$

$\small{\underline{\bf{Now, \:Distance \:between \:them\: =\: s_{2} - s_{1}}}_{}}$

$\hookrightarrow\:\:\:\sf 2000 - 1500$

$\hookrightarrow\:\:\:\bf \pink{500m} \\ \\$

${\underline{\bf{Hence, }}}$

Total Distance between them after $\bf{100 \:seconds}$ is $\bf\orange{500m}$

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To find what time does it take to reach maximum height we need to find how high will it go

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Knowing that its velocity is zero at its maximum height

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$0=(64ft/s)^2-2(32ft/s^2)(y-960ft)$

$y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft$

So, the projectile goes 1024 ft high

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$h=-16t^2+64t+960$

$1024=-16t^2+64t+960$

$0=-16t^2+64t-64$

Solving the quadratic equation

$t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}$

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$t=2s$

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

$v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})$

$v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s$

Since the projectile is going down the velocity at the instant it reaches the ground is:

$v=-256ft/s$

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