2 years ago

What is 1.3 for PE=mgh and for KE=1(m)v^2 and E=PE+KE and V

Physics

1 answer:

emmainna [20.7K]2 years ago

8 0

Answer:

1.3 is equal to m times v to the second times PK, meaning the answer to your question is 3.3 K

Explanation:

Have a gday!

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What is 1.3 for PE=mgh and for KE=1(m)v^2 and E=PE+KE and V​

What is 1.3 for PE=mgh and for KE=1(m)v^2 and E=PE+KE and V