The limiting reactant when 5.6 moles of aluminium react with 6.2 moles of water is
water( H2O)
<u><em>Explanation</em></u>
The balanced equation is as below
2 Al +3 H2O → Al2O3 +3 H2
The mole ratio of Al :Al2O3 is 2:1 therefore the moles of Al2O3
= 5.6 x1/2 = 2.8 moles
The mole ratio of H2O: Al2O3 is 3:1 therefore the moles of Al2O3 produced
= 6.2 x1/3= 2.067 moles
since H2O yield less amount of Al2O3 , H2O is the limiting reagent.
Answer:
this is basically structure of iso cyanic acid
Answer:
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Explanation:
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Answer:
Percent yield of CO₂ is 6.25 %.
Explanation:
Given data:
Percent yield of CO₂ = ?
Actual yield of CO₂ = 28.16 g
Number of moles of C₈H₁₈ = 8.000 mol
Number of moles of O₂ = 16.00 mol
Solution:
Chemical equation:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Now we will compare the moles of C₈H₁₈ and O₂ with CO₂.
C₈H₁₈ : CO₂
2 : 16
8.000 : 16/2×8.000 = 64 mol
O₂ : CO₂
25 : 16
16 : 16/25×16= 10.24 mol
Less number of moles of CO₂ are produced from 16 moles of O₂. it will limit the yield of CO₂.
Grams of CO₂ produced:
Mass = number of moles × molar mass
Mass = 10.24 mol × 44 g/mol
Mass = 450.56 g
Percentage yield of CO₂:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 28.16 g/ 450.56 g× 100
Percentage yield = 6.25 %