The mass of 254 mL of water is 254 g. Since the density of water is 1g/mL, we can simply multiply the density 1g/mL by 254 mL of water and get 254 g as our answer. Since mL is in the numerator and denominator, mL cancels out and we are left with g only.
Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius
Answer:
Approximately 
under standard conditions.
Explanation:
Equation for the overall reaction:
.
Write down the ionic equation for this reaction:
.
The net ionic equation for this reaction would be:
.
In this reaction:
- Zinc loses electrons and was oxidized (at the anode):
. - Copper gains electrons and was reduced (at the cathode):
.
Look up the standard potentials for each half-reaction on a table of standard reduction potentials.
Notice that is oxidation and is likely not on the table of standard reduction potentials. However, the reverse reaction, 
, is reduction and is likely on the table.
The reduction potential of would be 
, the opposite of the reverse reaction .
The standard potential of the overall reaction would be the sum of the standard potentials of the two half-reactions:
.
for
for