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tamaranim1 [39]
2 years ago
7

A box of total mass M is on a frictionless horizontal table. It is connected to a massless string that runs over a massless, fri

ctionless pulley. A box of mass m is suspended from the other end of the string. The system is released from rest. Inside the box of mass M, a small ball is suspended from a string. Derive an expression for the angle θ the string makes with the vertical, in terms of M and m. (Hint: you should first find the acceleration of the system.)
Physics
1 answer:
Sladkaya [172]2 years ago
4 0

Explanation:

v ysebhnnmmkkkjhgvbjuraatgvvf

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Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

    p₀o = m₁ v₁ + m₂ v₂

    pf = 0

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Another way to solve this exercise is to use the mass center relationship

    Xcm = 1/M    (m₁ x₁ + m₂ x₂)

We derive from time

   Vcm = 1/M   (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

    0 = 1/M   (m₁ v₁ + m₂v₂)

   m₁ v₁ + m₂v₂ = 0

    m₁ / m₂ = -v₂ / v₁

   m₁ / m₂ = 1.3

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