Meters Micrometers centimeters millimeters
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
<h3>
Work done by a single force on the chandelier</h3>
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
where;
is frictional force = 0 (smooth surface).
<h3>Work done by the two forces</h3>
When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Learn more about work done here: brainly.com/question/8119756
Answer:
a) 30 degree
Explanation:
As we know that time of flight of the projectile depends on the the vertical component of the velocity always
It is given as
now we know that
so we will have
since we know that two projectiles are projected at same speed but different angles
so smaller the angle will take smaller time
so it would be 30 degree projectile which will take smaller time
Bounce off of the object.
Hope this helps!
Answer:
Total revenue at the given price is 50625.
Explanation:
Price p = 45 - 0.01q
Revenue = Demand × Price
First derivative of R(q)
= 45 - 0.02q
45 - 0.02q = 0
-0.02q = -45
q = 2250
Second derivative of R(q)
= 0 - 0.02
= - 0.02
Since the second derivative is -ve it can be said that the revenue function has a maximum at q = 2250
The quantity that maximizes the revenue = 2250 items
Price of each item = 45 - 0.01 × 2250
= 45 - 22.50
Price of each item is 22.5
= 101250 - 50625
= 50625
Total revenue is 50625.