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Mumz [18]
2 years ago
6

What type of tool would best be used to map a section of the ocean floor?

Physics
2 answers:
vovikov84 [41]2 years ago
4 0
There are three tools used to map the ocean floor, sonar, satellites, and submersibles.
qwelly [4]2 years ago
3 0

Echo sounding is the key method scientists use to map,uses sound waves bounced off the ocean bottom.

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To meet the productivity goal, you must move 75 units of product per hour. You have moved 30 units of product in 30 minutes. How
9966 [12]

Answer:

1.5 unit of product per min

Explanation:

30 units of product was moved in 30 minutes.

Number of units left = Total number of units-number of units moved

                                =75-30 =45 units

45 units is available to be moved for the rest 30 min. To be able to achieve this goal of 75 units of product per hour.

45/30 amount of units must be moved in 1 min

=1.5 unit per min

4 0
3 years ago
Calculate the work done by an applied force of 76.0 N on a crate for the following. (Include the sign of the value in your answe
telo118 [61]

Answer:

a) 400.4Joules

b) 262.69Joules

Explanation:

Work is said to be done if the force applied to an object cause the object to move through a distance

Workdone = Force × Distance

Given

Force = 76N

Distance= 5.2m

Work done = 77 × 5.2

Work done = 400.4Joules

b) If the force is exerted at an angle of 41°

Work done = Fdsin theta

Work done = 77(5.2)sin41

Work done = 400.4sin41

Work done = 262.69Joules

6 0
3 years ago
Please help me with this question
ladessa [460]

Answer:

conduction

Explanation:

5 0
3 years ago
Read 2 more answers
I’ll give brainliest and 10 points
schepotkina [342]
I think it is D. I hope this helps
4 0
3 years ago
An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0V cell and a lamp rated at 300 mA, 3V. Calculate the cu
Alex

Answer:

I = 0.2 A

Explanation:

Lamp is rated at 300 mA

I_lamp = 0.3 A

Voltage is; V = 3V

Thus; Resistance is given by;

R = V/I

R = 3/0.3

R = 10 ohms

Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;

R_eq = 10 + 5

R_eq = 15 ohms

Ammeter current will be;

I = V/R_eq

I = 3/15

I = 0.2 A

3 0
2 years ago
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