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Mumz [18]
3 years ago
6

What type of tool would best be used to map a section of the ocean floor?

Physics
2 answers:
vovikov84 [41]3 years ago
4 0
There are three tools used to map the ocean floor, sonar, satellites, and submersibles.
qwelly [4]3 years ago
3 0

Echo sounding is the key method scientists use to map,uses sound waves bounced off the ocean bottom.

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A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has
erik [133]
Potential energy. When it starts moving, that potential energy will start transforming into kinetic energy.
3 0
3 years ago
What is latent heat energy's definiton
tamaranim1 [39]
The heat energy which has to be supplied to change the state of a substance is called its latent heat. Latent heat does not increase the kinetic energy of the particles of the substance, so the temperature of a substance does not rise during the change of state. :))
6 0
3 years ago
Kristine said that an ice cube gains heat when placed in a warm glass of water. Eric said that a hot cup of tea loses heat to co
Sindrei [870]

Answer:

Kristine is correct

Explanation:

this is because when an ice cube is placed into the warm water, it absorbs the heat from the water in order to melt which lowers the water's temperature.

in Eric's case, a hot cup of tea does not lose its heat because of cold hands. it varies depending on the cup whether it is a good insulator or not. also the heat can be lost through the air as well.

7 0
4 years ago
You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

3 0
4 years ago
Which statement most accurately compares earth crust and earth mantle
Aliun [14]

Answer:

  • Earth crust is thinner and less dense than the mantle.

  • Earth crust is thinner and less dense than the mantle.


7 0
3 years ago
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