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Mkey [24]
4 years ago
13

6 H2(g) + P4(5) → 4 PH:(9)

Chemistry
1 answer:
ira [324]3 years ago
7 0
C, I’m pretty sure. I think P4 is the limiting reactant
You might be interested in
2. Nitrogen has two naturally occurring
kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0
3 years ago
What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84?
Alexxandr [17]
<h3>Answer:</h3>

D. CH₃O₆

<h3>Explanation:</h3>
  • We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84

We are supposed to determine the empirical formula of the compound;

  • We need to know what is an empirical formula;
  • An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.

In this case;

The ratio of C : H : O is 14 : 42 : 84

  • Note, this is not the simplest ratio.

But we can simplify further to get the simplest whole number ratio;

  • Therefore, 14 : 42 : 84  is equal to 1 : 3 : 6
  • Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6
  • Therefore, the empirical formula of the compound is CH₃O₆
3 0
3 years ago
Determine the concentration of an unknown acid or base in a neutralization reaction
ryzh [129]
Titration is the process by which the concentration of an unidentified analyte is found
8 0
4 years ago
true or false: ionic bonding involves the shareing of electrons, oxide ions have a 2+ charge , electrons have a negative charge
Elis [28]
Ionic bonding does not involve the sharing of electrons, that one is false. In ionic bonding, the metal's electrons are given to the non-metal, so that they're both like the nearest noble gas (full electron shells.) They are then drawn together because one has a negative charge (the non-metal) and one has a positive charge (the metal.)

Oxide ions have a 2+ charge: This is false, oxide ions have a 2- charge.

Electrons do have a negative charge, this is true.

Hydrogen molecule: pretty sure this is true. We know this because both atoms are non-metals.

The last one is true: a covalent bond is a shared pair of electrons between two atoms, however be aware that there can be more than one covalent bond between two molecules.


7 0
3 years ago
Read 2 more answers
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
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