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Svetradugi [14.3K]
3 years ago
12

How much heat, in joules, is required to warm a metal disc from 19 °C to 33 °C? The

Chemistry
1 answer:
zalisa [80]3 years ago
3 0

Answer:

Q = 96.6 j

Explanation:

Given data:

Heat required = ?

Initial temperature = 19°C

Final temperature = 33°C

Mass of disc = 3.0 g

Specific heat capacity = 2.3 J/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33°C - 19°C

ΔT = 14°C

Q = 3.0 g×2.3 J/g.°C × 14°C

Q = 96.6 j

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3 years ago
A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.74 g of water at 52.2 oC in an insulated container. clead = 0.128
QveST [7]

Answer:

Explanation:

Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):

DH_{lead}=-DH_{water}

Now, by stating the heat capacity definition:

m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\

Solving for the equilibrium temperature:

T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC

Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.

Best regards.

5 0
3 years ago
What effect does observing a substance's physical properties have on the substance?
dybincka [34]
Depending on the testing process being used, it may affect the object by making it shape differently, scratch, it or sometimes do absolutely nothing.  hope this helps:)
5 0
3 years ago
Which reactants would lead to a spontaneous reaction?
balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

Atomic number of Mn is 25 and electronic configuration of Mn^{2+} is [Ar]4s^{0}3d^{5}. This configuration is stable.

Atomic number of Cr is 24 and electronic configuration of Cr is [Ar]4s^{1}3d^{5}. This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of Fe is [Ar]4s^{2}3d^{6}. This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of Cu^{2+} is [Ar]4s^{0}3d^{9}. This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of Ba^{2+} is [Kr]4d^{10}5s^{2}5p^{6}. This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of Mg^{2+} is 1s^{2}2s^{2}2p^{6}. This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]4d^{10}5s^{2}5p^{2}. This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and Cu^{2+} reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.


8 0
3 years ago
One of the most important aspects of a periodic table is that it _________________.
garri49 [273]
B) brings order to the elements. This is correct because elements are in order by highest atomic number.
5 0
3 years ago
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