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Dmitrij [34]
3 years ago
14

How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?

Chemistry
1 answer:
user100 [1]3 years ago
3 0
The amount of atoms of Phosphorus in 3.80 mol of copper (II) phosphate would be equivalent with :
3.80 mol x (6.022 x 10^23 molecules)/ (1 mol)

Hope this helps
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A phase diagram for elemental carbon is shown below.
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C.) lowering the pressure

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4 0
2 years ago
?cobalt has a density of 8.90 g. what volume would 17.8 g of Cobalt occupy?
Airida [17]

Answer:

Explanation:

Given parameters:

Density of cobalt = 8.9gcm⁻³

Mass of cobalt = 17.8g

Solution

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5 0
3 years ago
A piece of brass is found to have a mass of 24.32 g. When placed in a graduated cyclinder with an initial reading of 5.60 mL the
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Answer:

\rho=3.1g/mL

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

\rho =\frac{m}{V}

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

V=13.50mL-5.60mL=7.9mL

The density of the piece of brass turns out:

\rho =\frac{24.32g}{7.9mL}\\\\\rho=3.1g/mL

Best regards.

4 0
3 years ago
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