How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?
1 answer:
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From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n =
= 
= 11.46
where, P = pressure, V = volume occupied, n = number of moles of gas, R = universal gas constant=0.082L atm mol-1 K-1 and T = temperature.
Given: P = 2.8 atm, V = 98 l and T = 292 k.
Therefore n =
Answer: There are 0.056 moles present in 3.45 g of .
Explanation:
Given : Mass = 3.45 g
Moles is the mass of substance divided by its molar mass.
Hence, moles of (molar mass = 61.98 g/mol) is as follows.
Thus, we can conclude that there are 0.056 moles present in 3.45 g of .