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pashok25 [27]
3 years ago
14

What type of molecule is butanoic acid?

Chemistry
2 answers:
lutik1710 [3]3 years ago
7 0
Obtain b for example explain
ira [324]3 years ago
3 0

Answer:

option b.

Explanation:

<em>Carboxylic acid</em>

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What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5
djyliett [7]

Question:

What type of product forms in the intramolecular reaction between the aldehyde portion of the glucose molecule below and its C-5 hydroxyl group?  

a. disaccharide

b. carboxylic acid

c. hemiacetal

d. ester

e. stereoisomer

Answer:

hemiacetal  forms in the intramolecular reaction between the aldehyde portion of the glucose molecule and its C-5 hydroxyl group

Explanation:

It is an alcohol also an ether that has been attached to the carbon molecule. Here the hydrogen has occupied the fourth bonding position. This hemiacetal has been derived from the aldehyde. Hence, hemiketal being an alcohol as well as ether has been attached to the same carbon and also to the two other carbon.

7 0
3 years ago
A human zygote has 46 chromosomes. This number of chromosomes represents what in a human cell?
SOVA2 [1]
If the sperm carries a Y chromosome, it will result in a male. During fertilization, gametes from the sperm combine with gametes from the egg to form a zygote. The zygote contains two sets of 23 chromosomes, for the required 46.
3 0
3 years ago
If four hydrogen atoms react with two hydrogen atoms, how many atoms<br> will be in the product?
Ratling [72]

Answer:6

Explanation:

4 0
3 years ago
How many atoms are present in 65.39 g of zinc?
klio [65]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

 65.39 g Zn ( 1 mol / 65.38 g ) ( </span>6.022 x 10^23 atoms / 1 mol ) = 6.023x10^23 atoms Zn
3 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
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