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3 years ago

What type of molecule is butanoic acid?

Chemistry

2 answers:

lutik1710 [3]3 years ago

7 0

Obtain b for example explain

ira [324]3 years ago

3 0

Answer:

option b.

Explanation:

Carboxylic acid

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A____molecule is an example of a carbohydrate

denpristay [2]

I think it’s CTell me if I’m wrong

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3 years ago

Which statement is true regarding methane and ammonia?

sukhopar [10]

The options for given question are as follow,

1) Methane molecules show hydrogen bonding.
2) Ammonia molecules show hydrogen bonding. 
3) Methane has stronger hydrogen bonding than ammonia. 
4) Both the compounds do not show hydrogen bonding. 
5) Both the compounds have strong hydrogen bonding.

Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.

6 0

3 years ago

Read 2 more answers

Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s

bazaltina [42]

Answer: The time taken by the reaction is 84.5 seconds

Explanation:

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{9}=0.077s^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$ ......(1)

where,

k = rate constant = $0.077s^{-1}$

t = time taken for decay process = 50.7 sec

$[A_o]$ = initial amount of the reactant = ?

[A] = amount left after decay process = 0.0741 M

Putting values in equation 1, we get:

$0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}$

$[A_o]=3.67M$

Now, calculating the time taken by using equation 1:

$[A]=0.0055M$

$k=0.077s^{-1}$

$[A_o]=3.67M$

Putting values in equation 1, we get:

$0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s$

Hence, the time taken by the reaction is 84.5 seconds

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3 years ago

Compare the spectra produced by incandescent and fluorescent sources. Why is there a difference?

Inessa [10]

Both have a continuous light spectra the fluorescent source makes a spectra with more intense bands of mercury

5 0

3 years ago

Read 2 more answers

Which elements above will form cations? List them below.

cricket20 [7]

Answer:

Halogens always form anions, alkali metals and alkaline earth metals always form cations. Most other metals form cations (e.g. iron, silver, nickel), whilst most other nonmetals typically form anions (e.g. oxygen, carbon, sulfur).

Explanation:

Examples: Sodium (Na+), Iron (Fe2+), Ammonium (NH4

7 0

3 years ago