Answer:1). Distance of far point x=0.9m
Therefore, since the image is virtual
-f=-x = -0.9m
Power of the concave lenses = 1/f = 1/-0.9
= -1.11D
2 ) near point is 21cm = 0.21m
Power = 4-1/near point
= 4/0.21
= 14.2D.
50 strands is the standard procedure
Do you have any answer options?
The most I can help is to tell you that a covalent bond is a type of bond that shares electrons between the bonded atoms.
