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3 years ago

What is the duty of a choreographer?

Engineering

2 answers:

Sedbober [7]3 years ago

7 0

Answer:

designs and directs the dance or stylized movement in musical productions, working closely with the director and musical director. A choreographer works with dancers to interpret and develop ideas and transform them into the finished performance.

Explanation:

s2008m [1.1K]3 years ago

3 0

Answer:

A Choreographer designs and directs the dance or stylized movement in musical productions, working closely with the director and musical director. A choreographer works with dancers to interpret and develop ideas and transform them into the finished performance.

Explanation:

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A moving-coil instrument, which gives full-scale deflection with 0.015 A has a copper coil having resistance of 1.5 Ohm at 15°C

natulia [17]

Answer: check answers in pictures (2 p)

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3 years ago

Quantitative meaning

pychu [463]

Answer:

Explanation:

relating to, measuring, or measured by the quantity of something rather than its quality.Often contrasted with qualitative.

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3 years ago

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A steel with 1.0 % carbon is known as which one of the following: (a) eutectoid, (b) hypoeutectoid, (c) hypereutectoid, or (d) w

natta225 [31]

Answer:

Option c)

Explanation:

a.The carbon content of eutectoid steel, which is an carbon- iron alloy, is in between 0.80-0.83%

b. In hypoeutectoid steel, the carbon composition is less than 0.80% and is approximately 0.76%

c. In hypereutectoid steel, the carbon composition ranges from 0.80% - 2.0%

d. In wrought iron, the iron composition is quite low about 0.08%

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3 years ago

Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.

abruzzese [7]

Answer:

the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

Explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

SI unit IP unit Conversion factor

m ft 0.3048

W Btu/hr 0.293

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

$0.57\dfrac{Btu}{ft.hr.F}=1 \dfrac{W}{m.K}$

$0.57\times 14.54\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

$8.406\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}$

So the value of conductivity in IP is $8.406\dfrac{Btu}{ft.hr.F}$

7 0

3 years ago

Bananas are to be cooled from 24°C to 13°C at a rate of 215 kg/h by a refrigeration system. The power input to the refrigerator

Leni [432]

Answer:

a) $\dot Q_{L} = 132.046\,\frac{kJ}{min}$ , b) $COP_{R} = 1.467$

Explanation:

a) The heat rejected by the bananas is:

$\dot Q_{L} = \dot m \cdot c\cdot (T_{f}-T_{o})$

$\dot Q_{L} = \left(215\,\frac{kg}{h}\right)\cdot \left(\frac{1\,h}{60\,min} \right)\cdot \left(3.35\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (24^{\textdegree}C-13\,^{\textdegree}C)$

$\dot Q_{L} = 132.046\,\frac{kJ}{min}$

b) The coefficient of performance for the refrigeration system is:

$COP_{R} = \frac{\dot Q_{L}}{\dot W}$

$COP_{R} = \frac{\left(132.046\,\frac{kJ}{min}\right)\cdot \left(\frac{1\,min}{60\,s} \right)}{1.5\,kW}$

$COP_{R} = 1.467$

3 0

3 years ago