Answer:
People learn best in different ways. By combining all the group presentations, your class will explain how they see the optical illusion in a way that every student will be able to understand. Which presentation helped you understand how you saw the optical illusion best?
I cont under stand
Answer:
At the point of minimum pressure,
Solution:
As per the question;
Critical Mach no. for the air foil,
= 0.8
Now, for the value of the minimum pressure point:
Pressure of the air foil is critical, when
Now,
(1)
When M = 1:
(2)
When :
(3)
Now, from the eqns (1), (2) and (3):
Answer: False
Explanation: Sandwich materials are usually in composite material form which has a fabrication of two thin layers which are stiff in nature and have light weighing and thick core .The construction is based on the ratio that is of stiffness to the weight .Therefore, the density of the material in the core is not high and are only connected with the skin layer through adhesive .So the given statement is false that sandwich materials typically use a high density core with non- structural cover plates.
Magnitudes of the currents are i1= 0.00104A , i2= 0.003641A , i3= 0.00508A.
Explanation:
Using superposition theorem,
remove the E1 voltage supply source and calculate resistance across it.
From the circuit given, as the resistances R1 and R2 are parallel
using the formula R1//R2=(R1.R2/(R1+R3)
V1= ((r1||r2)/(r1+r2||r3))*E1
v1 = (((1kΩ*680Ω)/(1kΩ+680Ω))/(3.3kΩ +((1kΩ*680Ω)/(1kΩ+680Ω)))*10v
v1= 2.3v
v2 = ((r1||r2)/(r1+r2||r3))*E2
v2 = (((1kΩ*680Ω)/(1kΩ+680Ω))/(3.3kΩ +((1kΩ*680Ω)/(1kΩ+680Ω)))*5v
v2= 1.161v
V = V1+V2
=> 2.3 + 1.161
=> 3.461v
Magnitudes of the currents can be found by i=v/r
i1 = v/r1
=> 3.461/3.3kΩ
=>0.00104A
i2=2.89/1kΩ
=>0.003461A
i3=2.89/680Ω
=> 0.00508A.
Therefore the magnitudes of the currents are i1, i2, and i3.