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Leya [2.2K]
3 years ago
13

You are standing on the bottom of a lake with your torso above water. Which statement is correct?

Physics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

c. There is a buoyant force that is proportional to the volume of your body that is below the level of the water.

Explanation:

Buoyancy can be defined as a force which is created by the water displaced by an object.

Simply stated, buoyancy is directly proportional to the amount of water that is being displaced by an object.

Hence, the greater the amount of water an object displaces; the greater is the force of buoyancy pushing the object up.

The buoyancy of an object is given by the formula;

Fb = pgV

But, \; V = Ah

Hence, \; Fb = pgAh

Where;

Fb = buoyant force of a liquid acting on an object.

g = acceleration due to gravity.

p = density of the liquid.

v = volume of the liquid displaced.

h = height of liquid (water) displaced by an object.

A = surface area of the floating object.

The unit of measurement for buoyancy is Newton (N).

In this scenario, you are standing on the bottom of a lake with your torso above water. Thus, there is a buoyant force that is proportional to the volume of your body that is below the level of the water.

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A. is the one it did not say
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The length of a certain wire is kept same while its radius is doubled. what is the change in the resistance of this wire?
kaheart [24]
The resistance of a wire is given by
R= \frac{\rho L}{A}
where \rho is the resistivity of the material, L the length of the wire and A its cross-sectional area. 

In the problem, \rho and L remain the same, while A changes because the radius changes. The area is given by:
A=\pi r^2
This means that if we double the radius (2r), the area becomes
A_{new}= \pi (2r)^2 = 4 \pi r^2 =4A
And therefore, the new value of the resistance is
R_{new} =  \frac{\rho L}{4 A}= \frac{1}{4}R

So, when the radius is doubled, the resistance becomes \frac{1}{4} of its original value.
6 0
4 years ago
What distance will be traveled if you are going 120km/hr for 30 min? steps please
ArbitrLikvidat [17]
D= Speed x Time
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8 0
3 years ago
If a basball is project upwards from the ground level with an initial velovaity of 32 feet per second, then it's height is a fun
inessss [21]

Answer:

Maximum height reached by the ball is 32 meters.

Explanation:

It is given that,

If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :

s=-8t^2+32t...........(1)

t is the time taken

s is the height attained as a function of time.

Maximum height achieved can be calculated as :

\dfrac{ds}{dt}=0

\dfrac{d(-8t^2+32t)}{dt}=0

-16 t + 32 = 0

t = 2 seconds

Put the value of t in equation (1) as :

s=-8(2)^2+32(2)

s = 32 meters

So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.

6 0
4 years ago
A mass of 3.0 kg rests on a smooth surface inclined 34° above the horizontal. It is kept from sliding down the plane by a spring
azamat

Answer:

The spring stretched by x = 13.7 cm

Explanation:

Given data

Mass = 3 kg

k = 120 \frac{N}{m}

Angle \theta = 34°

From the free body diagram

Force acting on the box = mg sin\theta

⇒ F = 3 × 9.81 × \sin34

⇒ F = 16.45 N ------- (1)

Since box is attached with the spring so a spring force also acts on the box.

F_{sp} = k x

F_{sp} = 120 x -------- (2)

The net force acting on the body is given by

F_{net} = ma

Since acceleration of the box is zero so

F_{net} = 0

F - F_{sp} = 0

F = F_{sp}

Put the values from equation (1) & (2) we get

16.45 = 120x

x = 0.137 m

x = 13.7 cm

Therefore the spring stretched by x = 13.7 cm

3 0
3 years ago
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