Answer:
The repulsive electrostatic force between two of the protons is 14.4 N.
Explanation:
Given;
distance between the two protons, r = 4 x 10⁻¹⁵ m
charge of a proton, q = + 1.6 x 10⁻¹⁹ C
The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;
Therefore, the repulsive electrostatic force between two of the protons is 14.4 N.
Average velocity is defined as
now we have
when she cross the pool in time t1
when she cross the pool back to starting position
Here negative sign is for its return path direction which is reversed of its initial direction.
now for the round trip
displacement = 0
so v = 0
Answer:
v=1.5081 m/s
Explanation:
<u>Uniform Circular Motion
</u>
The cork is performing a circular motion which we assume to be uniform (constant angular speed or angular acceleration zero)
The centripetal force applied to it is given by
where m is the mass and is the centripetal acceleration. This acceleration appears since the tangent speed is constantly changing direction. If w is the angular speed and r is the radius of rotation
The speed of the cork can be found with the formula
We can compute w since we know the rotation period <em>T=1.25 sec
</em>
Now, since r=0.30 m, let's compute v
And finally
<span>Ionospheric interactions with radiation </span>