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Softa [21]
3 years ago
5

Calculate the power if the current in a circuit is 3A and the resistance of the circuit is 50hms

Physics
1 answer:
Tresset [83]3 years ago
3 0

Answer:

450W

Explanation:

V= I*R

V=3A*50 Ohms

V=150V

P=I*V

P=3A*150V

P=450W

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Two pipes move the same amount of ideal fluid in the same amount of time. One pipe has a 2 in. diameter; the other has a 3 in. d
KATRIN_1 [288]

Answer:

a) 3-in. pipe

Explanation:

Given that

Fluid flow is in same amount in the same time it means that volume flow rate is same for the pipes

Volume flow rate

Q = A V

A=Area ,V=Velocity

A=\dfrac{\pi}{4}d^2

If diameter d is more then the velocity will be less for same volume flow rate .We also Know that if pressure is more then the velocity will be less.

The second pipe 3 in diameter having more diameter then the velocity will be less but the pressure will be more.

That is why the 3 in diameter is having more pressure than 2 in diameter pipe.

Therefore the answer will be a.

a) 3-in diameter  pipe

6 0
3 years ago
A 1.30-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v
atroni [7]

Answer:

1. t = 0.0819s

2. W = 0.25N

3. n = 36

4. y(x , t)= Acos[172x + 2730t]

Explanation:

1) The given equation is

y(x, t) = Acos(kx -wt)

The relationship between velocity and propagation constant is

v = \frac{\omega}{k}=\frac{2730rad/sec}{172rad/m}\\\\

v = 15.87m/s

Time taken, t = \frac{\lambda}{v}

= \frac{1.3}{15.87}\\\\=0.0819 sec

t = 0.0819s

2)

The velocity of transverse wave is given by

v = \sqrt{\frac{T}{\mu}}

v = \sqrt{\frac{W}{\frac{m}{\lambda}}}

mass of string is calculated thus

mg = 0.0125N

m = \frac{0.0125N}{9.8N/s}

m = 0.00128kg

\omega = \frac{v^2m}{\lambda}

\omega = \frac{(15.87^2)(0.00128)}{1.30}

\omega = 0.25N

3)

The propagation constant k is

k=\frac{2\pi}{\lambda}

hence

\lambda = \frac{2\pi}{k}\\\\\lambda = \frac{2 \times 3.142}{172}

\lambda = 0.036 m

No of wavelengths, n is

n = \frac{L}{\lambda}\\\\n = \frac{1.30m}{0.036m}\\

n = 36

4)

The equation of wave travelling down the string is

y(x, t)=Acos[kx -wt]\\\\becomes\\\\y(x , t)= Acos[(172 rad.m)x + (2730 rad.s)t]

without, unit\\\\y(x , t)= Acos[172x + 2730t]

7 0
3 years ago
If the amplitude of a simple harmonic oscillator is doubled, by what factor does the total energy increase?
dybincka [34]

Answer:

c)by a factor of four

Explanation:

The total energy of a simple harmonic oscillator is given by

E=\frac{1}{2}kA^2

where

k is the spring constant of the oscillator

A is the amplitude of the motion

In this problem, the amplitude of the oscillator is doubled, so

A' = 2A

Therefore, the new total energy is

E'=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E

So, the total energy increases by a factor 4.

6 0
3 years ago
Suppose that a sound wave has a wavelength of 12 meters and a frequency of 100Hz. What is the speed of sound
Vesna [10]

Answer:

1200Hz

Explanation:

You would have to multiply 12 by 100 to get the answer.


12 • 100 = 1200 Hz


I hope it helps! Have a great day!

Anygays-

8 0
2 years ago
Jane is a team leader. Match her leadership and teamwork skills to the appropriate descriptions.making her team understand the r
gtnhenbr [62]
Jane is motivating and empowering her team.
7 0
3 years ago
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