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larisa86 [58]
2 years ago
14

A force generated by an underwater earthquake applied to oceans waves over a period of time changes the wave's momentum, this is

referred to as _____.
Physics
1 answer:
stich3 [128]2 years ago
6 0

<u>Answer</u>:

A force generated by an underwater earthquake applied to the waves of the ocean during a period changes the momentum of the wave, this is referred to as tsunami.

<u>Explanation</u>:

Most of the tsunamis are caused due to earthquakes and are the most destructive. When an earthquake of magnitude more than 7.5 in the Richter scale hits the ocean, there is a huge stir on the river and the balance of the water above it deteriorates. Waves are produced when water tries to get back its equilibrium.

This wave is formed due to the rise in water at the epicenter of the crisis and moves around the epicenter in the form of concentric circles. Remember that not all the earthquakes cause tsunamis, but in the same situation when the earthquake causes a movement in the seawater in the vertical direction. This movement arises on the ocean floor due to earthquakes, fractures or the sliding of plates.

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3 years ago
You pull on a spring whose spring constant is 22 N/m, and stretch it from its equilibrium length of 0.3 m to a length of 0.7 m.
Liono4ka [1.6K]

Answer:

W= 4.4 J

Explanation

Elastic potential energy theory

If we have a spring of constant K to which a force F that produces a Δx deformation is applied, we apply Hooke's law:

F=K*x  Formula (1): The force F applied to the spring is proportional to the deformation x of the spring.

As the force is variable to calculate the work we define an average force

F_{a} =\frac{F_{f}+F_{i}  }{2}  Formula (2)

Ff: final force

Fi: initial force

The work done on the spring is :

W = Fa*Δx

Fa : average force

Δx :  displacement

W = F_{a} (x_{f} -x_{i} )   :Formula (3)

x_{f} :  final deformation

x_{i}  :initial deformation

Problem development

We calculate Ff and Fi , applying formula (1) :

F_{f} = K*x_{f} =22\frac{N}{m} *0.7m =15.4N

F_{i} = K*x_{i} =22\frac{N}{m} *0.3m =6.6N

We calculate average force applying formula (2):

F_{a} =\frac{15.4N+6.2N}{2} = 11 N

We calculate the work done on the spring  applying formula (3) :         :

W= 11N*(0.7m-0.3m) = 11N*0.4m=4.4 N*m = 4.4 Joule = 4.4 J

Work done in stages

Work is the change of elastic potential energy (ΔEp)

W=ΔEp

ΔEp= Epf-Epi

Epf= final potential energy

Epi=initial potential energy

E_{pf} =\frac{1}{2} *k*x_{f}^{2}

E_{pi} =\frac{1}{2} *k*x_{i}^{2}

E_{pf} =\frac{1}{2} *22*0.7^{2} = 5.39 J

E_{pf} =\frac{1}{2} *22*0.3^{2} = 0.99 J

W=ΔEp=  5.39 J-0.99 J = 4.4J

:

4 0
2 years ago
You make a(n) _____ by fastening together usually perpendicular parts with the ends cut at an angle.
nadezda [96]

Answer:

Miter joint

Explanation:

Made by fastening together usually perpendicular parts with the ends cut at an angle

8 0
2 years ago
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