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inna [77]
3 years ago
11

Which of the following conclusions can be drawn from the curves in the

Chemistry
2 answers:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

The answer is (B. pls mark brainliest and good luck :D

sukhopar [10]3 years ago
5 0

Answer:

The answer is C

Explanation:

just had this :)

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What is true about the number of water particles in the pot after the water has been warmed?
Elza [17]

Answer:ye

Explanation:

8 0
3 years ago
A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its KspKsp a
trapecia [35]

Answer:

10.945 x 10^-4

Explanation:

Balanced equation:

Mn(OH)2 +  2 HCl  -->  MnCl2  +  H2O

it takes 2 moles HCL for each mole Mn(OH)2

Next find the molarity of the Mn(OH)2 solution

= (1 mole Mn(OH)2 / 2 mole HCl)  X (0.0020 mole HCl / 1000ml) X (4.86 ml)    

= 4.86 x 10^-3 mole  

this is now dissolved in (70 + 4.86)  =  74.86 ml or 0.07486 L

thus [Mn(OH)2]  =  4.86 x 10^-3 mole / 0.07486 L  =  0.064921 M

Ksp =  [Mn2+][OH-]^2  =  4x^3  =  4(0.064921)^3  = 10.945 x 10^-4

6 0
3 years ago
The transfer of a section of DNA from one organism into the DNA of another organism by scientist is called
denpristay [2]
Transgenetics

hope this helps!
5 0
4 years ago
Vinegar 59g, Oil 177g, Brown sugar 10g, and total mass
denis-greek [22]

Answer:

Total mass = 246 g

Explanation:

Given data:

Mass of vinegar = 59 g

Mass of oil = 177 g

Mass of brown sugar = 10 g

Total mass = ?

Solution:

Total mass = masses of [sugar + oil + vinegar]

Total mass = 59 g + 177 g + 10 g

Total mass = 246 g

3 0
3 years ago
What is the density at 20 degrees Celsius of 12.0 mL of a liquid that has a mass of 4.05g?​
zmey [24]

Answer:

<h3>The answer is 0.34 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{4.05}{12}  \\  = 0.3375

We have the final answer as

<h3>0.34 g/mL</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
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