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Degger [83]
2 years ago
9

A 0.4 m long solenoid has a total of 356 turns of wire and carries a current of 79 A. What is the magnitude of the magnetic fiel

d at the center of the solenoid?
Physics
1 answer:
Masja [62]2 years ago
5 0

Answer:

B = 0.088 T

Explanation:

Given that,

The length of a solenoid, l = 0.4 m

No. of turns of wire, N = 356

Current, I = 79 A

We need to find the magnitude of the magnetic field at the center of the solenoid. It is given by the formula.

B=\mu_onI\\\\B=\mu_o \dfrac{N}{l}\times I\\\\B=4\pi \times 10^{-7}\times \dfrac{356}{0.4}\times 79\\\\B=0.088\ T

So, the magnitude of the magnetic field at the center of the solenoid is 0.088 T.

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426.84 m

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2 years ago
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