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vodomira [7]
3 years ago
8

Why the brakes of a car gets hotter than the brakes of a bicycle?

Physics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

Frictional force

Explanation:

The brakes of a car gets hotter than the brakes of a bicycle because more frictional force is expended in applying the brake on a car than a bicycle.

To brake a car, the concept of friction is usually adopted. Two surfaces that increases friction when they come in contact are used in braking.

Frictional force is a force that resists the motion of a body. This forces helps to have grasp of motion.

A car requires more resistance to motion to break it because it have more more mass and other component motions parameters.

A bicycle is lighter and will require little friction.

Some of the frictional force applied is converted to heat energy. The amount of this energy expended is proportional to the frictional force.

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Igneous rocks

Explanation:

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3 years ago
Two containers (A and B) are in thermal contact with an environment at temperature T = 280 K. The two containers are connected b
zmey [24]

Answer:

The maximum amount of work is  W = 1563.289 \ J

Explanation:

From  the question we are told that

   The temperature of the environment is  T = 280\ K

    The volume of container A is  V_A = 2 m^3

    Initially the number of moles  is  n = 1.2 \ moles

     The volume of container B is V_B = 3.5 \ m^3

     

At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as

             W =  P_A V_A  ln[ \frac{V_B}{V_A} ]

Now from the Ideal gas law

          P_A V_A =  nRT

So substituting for P_A V_A in the equation above

          W =  nRT ln [\frac{V_B}{V_A} ]

Where R is the gas constant with a values of  R =  8.314 \  J/mol

Substituting values we have that

            W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]

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8 0
3 years ago
How does the size of a planet affected the amount and type of gas in its atmosphere
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A force of 150 N is applied to a 25 cm- piston in a hydraulic machine. What is the area
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8.3 cm^2

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A 0.2-kg steel ball is dropped straight down onto a hard, horizontal floor and bounces straight up. The ball's speed just before
nadya68 [22]

Answer:

Explanation:

Given

mass of steel ball m=0.2\ kg

initial speed of ball u=10\ m/s

Final speed of ball v=-10\ m/s (in upward direction)

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therefore impulse J is given by

J=\Delta P

\Delta P=m(v-u)

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\Delta =-4\ N-s

so magnitude of Impulse =4 N-s

7 0
3 years ago
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