The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>
The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;
![\rm \frac{1}{f} =\frac{1}{v} +\frac{1}{u} \\\\\ \frac{1}{15}=\frac{1}{v}+\frac{1}{10} } \\\\\ v= -30 \ cm](https://tex.z-dn.net/?f=%5Crm%20%5Cfrac%7B1%7D%7Bf%7D%20%3D%5Cfrac%7B1%7D%7Bv%7D%20%2B%5Cfrac%7B1%7D%7Bu%7D%20%5C%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7B15%7D%3D%5Cfrac%7B1%7D%7Bv%7D%2B%5Cfrac%7B1%7D%7B10%7D%20%7D%20%20%5C%5C%5C%5C%5C%20v%3D%20-30%20%5C%20cm)
The magnification of the lens is found as;
![\rm m=\frac{30}{10}\\\\ m=3](https://tex.z-dn.net/?f=%5Crm%20m%3D%5Cfrac%7B30%7D%7B10%7D%5C%5C%5C%5C%20m%3D3)
Hence, the image distance and magnification of The image will be 30 cm and 3.
To learn more about the focal length refer;
brainly.com/question/16188698
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Need more info.
It depends on what the job is.
Answer: parallel
Explanation:
frictional force acts parallel to a surface and resists the motion of an object
<span>As the body rises up its gravitational potential energy increases but its kinetic energy decreases.
As a body falls its gravitational potential energy decreases but it's kinetic energy increases</span>