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kotegsom [21]
3 years ago
7

What is the mass % of acetone in a 1.77 M solution of acetone (MM = 58.08 g/mol) in water? The density of the solution is 0.971

g/mL.
Chemistry
1 answer:
bija089 [108]3 years ago
6 0

Answer:

\%m/m=10.6\%

Explanation:

Hello!

In this case, since the by-mass percent is defined by:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

Thus, since the given 1.77 M solution is given in terms of mol/L, we need to compute the mass of acetone via its molar mass and the volume of solution in L to g via the density:

\%m/m=1.77\frac{mol}{L}*\frac{58.08g}{1mol}*\frac{1L}{1000mL}*\frac{1mL}{0.971g}   *100\%\\\\\%m/m=10.6\%

Best regards!

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