Answer:
1) The value of Kc:
C. remains the same.
2) The value of Qc:
A. is greater than Kc.
3) The reaction must:
B. run in the reverse direction to restablish equilibrium.
4) The concentration of N2 will:
B. decrease.
Explanation:
Hello,
In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:
1) The value of Kc:
C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:
2) The value of Qc:
A. is greater than Kc, since the reaction quotient is:
Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.
3) The reaction must:
B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.
4) The concentration of N2 will:
B. decrease, since less reactant is forming the products.
Best regards.
answer: C) 1.6 g
explanation: Molarity is the moles of solute present per liter solution.
The given molarity of the solution is 0.01 M.
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Answer:
pH = 1.85
Explanation:
The reaction of H₂NNH₂ with HNO₃ is::
H₂NNH₂ + HNO₃ → H₂NNH₃⁺ + NO₃⁻
Moles of H₂NNH₂ and HNO₃ are:
H₂NNH₂: 0.0400L ₓ (0.200mol / L) = 8.00x10⁻³ moles of H₂NNH₂
HNO₃: 0.1000L ₓ (0.100mol / L) = 0.01 moles of HNO₃
As moles of HNO₃ > moles of H₂NNH₂, all H₂NNH₂ will react producing H₂NNH₃⁺, but you will have an excess of HNO₃ (Strong acid).
Moles of HNO₃ in excess are:
0.01 mol - 8.00x10⁻³ moles = 2.00x10⁻³ moles of HNO₃ = moles of H⁺
Total volume is 100.0mL + 40.0mL = 140.0mL = 0.1400L.
Thus, [H⁺] is:
[H⁺] = 2.00x10⁻³ moles / 0.1400L = 0.0143M
As pH = - log [H⁺]
<h3>pH = 1.85 </h3>
Answer:
gasese molecules are always in free state