Answer:
2 in front of water and 1 in front of oxygen
Explanation:
Answer:
579600J
Explanation:
Given parameters:
Height of the building = 828m
Weight of the man = 700N
Unknown:
Work done by the man = ?
Solution:
The work done by the man is the same as the potential energy expended.
Work done:
Work done = Weight x height = 700 x 828
Work done = 579600J
Answer:
I₂ = 8 mG
Explanation:
The intensity of a beam is
I = P / A
Where P is the emitted power which is 3) 3
Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft
I₁ A₁ = I₂ A₂
I₂ = I₁ A₁ / A₂
The area of the beam if we assume that it is distributed either in the form of a sphere is
A₁ = 4π r²
We substitute
I₂ = I₁ (r₁ / r₂)²
I₂ = 2 (6/3)²
I₂ = 2 4
I₂ = 8 mG
Answer:
to be seen correctly and throughly
Explanation:
EE = ½ kx²
EE = ½ (0.55 N/m) (0.15 m)²
EE = 0.62 J
