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Dmitry [639]
1 year ago
14

CER (claim, evidence, reasoning)

Physics
1 answer:
ira [324]1 year ago
6 0

The reasoning that can be used to agree with the claim that has ben made is that the human powered generators are the best due to the fact that they would not have to require the long time and they would not have to consume resources.

<h3>What is a claim?</h3>

This is the term that is used to refer to a statement or an assertion that has been made which has not yet been proven.

The human powered generators are the best due to the fact that they would not require the resources that are known to be more consuming. That is they are renewable and like fossils they would not have any forms of adverse effects on the environment that they are used.

Read more on human powered generators here: brainly.com/question/18287444

#SPJ1

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Think about lifestyle choices that you make on a daily basis. Choose at least four lifestyle choices which you could change to i
eimsori [14]
A.The four lifestyle choices which I could change are:
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4 0
3 years ago
What is the conclusion of coin and feather experiment? ​
valina [46]

Answer:

So the conclusion is that in presence of air net force acting downward reduces for feather and hence falls slower than coin. But in absence of air resistance, net downward force is just equal to force due to gravity which is same for both coin and feather and hence they fall down at the same rate.

5 0
3 years ago
A 0.20 kg mass on a horizontal spring is pulled back a certain distance and released. The maximum speed of the mass is measured
xxMikexx [17]

Answer:

b. 0.20 m/s.

Explanation:

Given;

initial mass, m = 0.2 kg

maximum speed,  v = 0.3 m/s

The total energy of the spring at the given maximum speed is calculated as;

K.E = ¹/₂mv²

K.E = 0.5 x 0.2 x 0.3²

K.E = 0.009 J

If the mass is changed to 0.4 kg

¹/₂mv² = K.E

mv² = 2K.E

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2\times 0.009}{0.4} } \\\\v = 0.21 \ m/s\\\\v \approx 0.20 \ m/s

Therefore, the maximum speed is 0.20 m/s

4 0
3 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

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s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
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Sedbober [7]

Answer:

377 nm

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Number of lines per meter is, N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}

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=1.8868 \times 10^{-6} \mathrm{~m}[tex]&#10;Order is, n=5&#10;Condition for maximum intensity is, [tex]d \sin \theta=n \lambda

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