Answer:
t = 4.08 s
R = 40.8 m
Explanation:
The question is asking us to solve for the time of flight and the range of the rock.
Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:
We have these known variables:
- (v_0)_y = 0 m/s
- a_y = -9.8 m/s²
- Δx_y = -20 m
And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.
- -20 = 0t + 1/2(-9.8)t²
- -20 = 1/2(-9.8)t²
- -20 = -4.9t²
- t = 4.08 sec
The time it takes for the rock to reach the ground is 4.08 seconds.
Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.
List out known variables:
- v_0 = 10 m/s
- t = 4.08 s
- a_x = 0 m/s
We are trying to solve for:
By using the same equation, we can plug these known values into it and solve for Δx.
- Δx = 10 * 4.08 + 1/2(0)(4.08)²
- Δx = 10 * 4.08
- Δx = 40.8 m
The rock lands 40.8 m from the base of the cliff.
Answer:
b. unity
Explanation:
In the images I added you can observe Atsuko Tanak's works, in both of them you can observe how <em>the sum of colorful and repetitive elements creates the sensation of unity.</em>
I hope you find this information useful and interesting! Good luck!
To answer your question it is true
Answer: a) 24.2 rad/s² b) 6.95 rad/s
Explanation:
So the cylinder's moment of inertia is , where M is the mass of the cylinder and R is its radius.
The problem you have here is that the axle is modifying it, so we use the parallel axis theorem:
Therefore
where D is the distance from the center of mass to the axis which is a radius R
Next the Momentum with respect to the center of mass of the cylinder is
because there are no other forces rather than the cylinder's weight, now kg*m^2
a ) replace and find
b) we start by assuming that the energy is conserved because the cylinder is rolling without sliding:
so the potential energy is given by
now you have that the same amount is going to be equal to the kinetic rotational energy of the cylinder so
Answer:
low amplitude hope it will help you