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MAXImum [283]
3 years ago
8

A solid metal ball with a mass of 10.0 kg is placed on a smooth floor what force would be needed to accelerate the ball at a rat

e of 2.0 m/s2.
40 N
20 N
5 N
0.2 N
Physics
1 answer:
miv72 [106K]3 years ago
7 0
20n no doubt because the 10.0 / 2.0
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Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
lawyer [7]

Answer:

A is the answer!

Explanation:

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3 years ago
An instrument that can detect the presence of an electric charge is a
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Electroscope is the instrument that has the ability to detect the presence of an electric charge. Although electroscope has the power to measure the amount of charge, but for a perfect measurement the electrometer is used. Around the year 1600, electroscope was discovered by William Gilbert he British physician. This is a pretty primitive but highly effective instrument in regards to detecting the presence of electric charges. Two basic but effective electroscopes are the gold-leaf electroscope and the pith-ball electroscope.
5 0
4 years ago
5. A little boy tries to push a heavy cupboard. He uses a force of 400 N, but he is unable to move
ad-work [718]

Answer:

NO HAY TRABAJO REALIZADO YA QUE EL NIÑO NO PUDO MOVER

EL ARMARIO, PARA QUE HAYA TRABAJO DEBE HABER DESPLAZAMIENTO.

Explanation:

8 0
3 years ago
Eld a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 3.1
zheka24 [161]

Answer:

v_{f}=1721.1m/s

Explanation:

Given data

q = 3.1 µC

m = 47 mg

r1 = 0.83 mm

r2 = 2.5 mm.

As we know that:

dK=-dU\\(1/2)mv_{f}^{2}-(1/2)mv_{i}^{2}=-(\frac{kq^{2} }{r_{f}}-\frac{kq^{2} }{r_{i}} )\\    (1/2)*(47*10^{-6}kg )v_{f}^{2}-(1/2)*(47*10^{-6}kg)(0)=-[(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{2.5*10^{-3}}-(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{0.83*10^{-3}} )]\\2.35*10^{-5} v_{f}^{2}=69.61\\v_{f}=\sqrt{\frac{69.61}{2.35*10^{-5}} }\\v_{f}=1721.1m/s

5 0
3 years ago
A light beam is traveling through an unknown substance. When it exits that substance and enters into air, the angle of reflectio
bogdanovich [222]

Answer:

0.79

Explanation:

Using Snell's law, we have that:

n(1) * sin θ1 = n(2) * sinθ2

Where n(1) = refractive index of air = 1.0003

θ1 = angle of incidence

n(2) = refractive index of second substance

θ2 = angle of refraction

The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°

=> 1.0003 * sin32 = n(2) * sin42

n(2) = (1.0003 * sin32) / sin42

n(2) = 0.79

3 0
3 years ago
Read 2 more answers
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