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Gala2k [10]
3 years ago
6

Lab: Newton’s Second Law Assignment: Lab Report Will give 100 points

Physics
2 answers:
weeeeeb [17]3 years ago
7 0

Answer:

do yall have the whole lab

im doing it today... and im very stuck

plz help

Explanation:

Ad libitum [116K]3 years ago
4 0

Answer:

The objective of this lab is to explore and analyze the relationship between force, mass, and acceleration. Theory. According to Newton's Second Law, the acceleration, a, of a body is directly proportional to the vector sum of the forces, ΣF, applied to the body: ΣF = ma (5.1) where m is the mass of the body.

Explanation:

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The formula relating acceleration and angular velocity is:

a = ω^2 r

where a is acceleration, ω is angular velocity and r is radius

But the angular velocity ω is constant all throughout the disk therefore:

a1 / r1 = a2 / r2

 

So at points:

<span>r1 = 0.0130 m     -> a1 = 393 m/s^2</span>

<span>r2 = 0.0884 m     -> a2 = ?</span>

 

393 / 0.0130 = a2 / 0.0884

<span>a2 = 2,672.4 m/s^2</span>

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3 years ago
Waves of energy in the electromagnetic spectrum travel through space and into the earths atmosphere. Which waves pass more crest
andrew-mc [135]
The answer is D.......
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4 years ago
The displacement of a wave traveling in the positive x-direction is y(x, t)|= (3.5 cm)cos(2.7x − 92t), where x is in m and t is
zubka84 [21]

Answer

Given,

y(x, t) = (3.5 cm) cos(2.7 x − 92 t)

comparing the given equation with general equation

y(x,t) = A cos(k x - ω t)

 A = 3.5 cm  , k = 2.7 rad/m    , ω = 92 rad/s

we know,

a) ω =2πf

   f = 92/ 2π

   f = 14.64 Hz

b) Wavelength of the wave

 we now, k = 2π/λ

      2π/λ = 2.7

      λ = 2 π/2.7

      λ = 2.33 m

c) Speed of wave

     v = ν λ

     v = 14.64 x 2.33

     v = 34.11 m/s

5 0
4 years ago
HELP 30 POINTS
DENIUS [597]

Mid-ocean ridges happen along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing large volcanic eruptions of basalt.

7 0
3 years ago
A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
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