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slega [8]
3 years ago
10

A balloon that can hold 85 L of air is inflated with 7.056 grams of H2 gas at a pressure of 101.3 kPa. What is the temperature,

in Celsius, of the balloon.
Chemistry
1 answer:
evablogger [386]3 years ago
8 0
<h2>Answer:</h2>

Temperature is 258.32°C

<h2>Explanation:</h2>

Using the ideal gas equation;

PV = nRT        --------------(i)

Where;

P = Pressure of the gas

V = Volume of the gas

n = number of moles of the gas

R = Gas constant = 8.31 J/mol · K

T = Temperature

<em><u>Given:</u></em>

mass of H₂ gas = 7.056 grams

Volume of the gas = 85L = 8.5 x 10⁻³m³

Pressure of the gas = 101.3kPa = 101.3 x 10³Pa = 1.013 x 10⁵Pa

<em><u>Steps:</u></em>

(i) Using the mass of the gas, calculate the number of moles using the relation:

n = m / M         ----------------- (ii)

Where;

m = mass of H₂ = 7.056g

M = Molar mass of H₂ = 1g/mol

<em>Substitute these values into equation (ii) as follows:</em>

n = 7.056g / (1g/mol)

n = 7.056mol

(ii) Now calculate the temperature of the balloon by substituting the necessary values into equation (i)

(1.013 x 10⁵Pa)(8.5 x 10⁻³m³) = (7.056mol) (8.31 J/mol · K)(T)

T = (1.013 x 10⁵Pa)(8.5 x 10⁻³m³) ÷ (7.056mol) (8.31 J/mol · K)

<em>Solving the above gives</em>

T = 14.68K

<em>Convert this to Celsius </em>

T = 273 - 14.68

T = 258.32°C

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21+ Cl2 → 12+201 -
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Answer:

\rm 2\; I^{-} + Cl_2 \to I_2 + 2 \; Cl^{-}.

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End color: dark purple.

Assumption: no other ion in the solution is colored.

Explanation:

In this reaction, chlorine gas \rm Cl_2 oxidizes iodine ions \rm I^{-} to elemental iodide \rm I_2. At the same time, the chlorine atoms are converted to chloride ions \rm Cl^{-}.

Fluorine, chlorine, bromine, and iodine are all halogens. They are all found in the 17th column of the periodic table from the left. One similarity is that their anions are not colored. However, their elemental forms are typically colored. Besides, moving down the halogen column, the color becomes darker for each element.

Among the reactants of this reaction, \rm I^{-} is colorless. If there's no other colored ion, only the yellowish-green hue of \rm Cl_2 would be visible. Hence the initial color of the reaction would be the yellowish-green color of \rm Cl_2.

Similarly, among the products of this reaction, \rm Cl^{-} is colorless. If there's no other colored ion, only the dark purple hue of \rm I_2 would be visible. Hence the initial color of the reaction would be the dark purple color of \rm I_2.

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3 years ago
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Answer:

The new volume of a gas at 750 mmhg and with a volume of 2. 00 l when allowed to change its volume at constant temperature until the pressure is 600 mmhg is 2.5 Liters.

Explanation:

Boyle's law states that the pressure of a given amount of gas is inversely proportional to it's volume at constant temperature. It is written as;

P ∝ V

P V = K

P1 V1 = P2 V2

Parameters :

P1 = Initial pressure of the gas = 750 mmHg

V1 = Initial pressure of the gas = 2. 00 Liters

P2 = Final pressure of the gas = 600 mmHg

V2 = Fimal volume of the gas = ? Liters

Calculations :

V2 = P1 V1 ÷ P2

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V2 = 1500 ÷ 600

V2 = 2.5 Liters.

Therefore, the new volume of the gas is 2. 5 Liters.

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