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frosja888 [35]
3 years ago
7

???????????!??!!!!!!!!​

Physics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0
The answer would be B.

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A car travels 200km in the first 2.5 hours of a trip. it stops half am hour and then travels final 200km in 2 hours. find the av
aksik [14]

Answer:

total distance 400km

time 4.5

average speed is 100km

7 0
3 years ago
A box is pushed 40 m by a mover. The amount of work done was 2,240 j. How much force was exerted on the box
Georgia [21]

The force exerted on the box is 56 N

Explanation:

The work done by a force on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

W = 2240 J is the work done

d = 40 m is the displacement of the box

Assuming that the  force is parallel to the displacement, \theta=0

Solving the equation for F, we find the force exerted on the box:

F=\frac{W}{d cos \theta}=\frac{2240}{(40)(cos 0)}=56 N

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

3 0
3 years ago
If it takes 560 joules of work to move an object 10 meters what force was needed
Pavel [41]

Answer:

F = 56 N

Explanation:

  • Assuming that the applied force is parallel to the displacement, according to the definition of work, we can write the following expression for the force required:

       F = \frac{W}{\Delta x} =\frac{560J}{10m} = 56 N (1)

6 0
3 years ago
A charge Q is transferred from an initially uncharged plastic ball to an identical ball 17 cm away. The force of attraction is t
Alecsey [184]

Answer:

2.92 x 10¹² electrons

Explanation:

given,

distance between two plastic ball, r = 17 cm

                                      r = 0.17 m

Force of attraction = F = 68 mN

                F = 0.068 N

number of electron transferred from one ball to another.

using Coulomb Force equation

F = \dfrac{kq^2}{r^2}

0.068 = \dfrac{9\times 10^9\times q^2}{0.17^2}

q² = 2.1835 x 10⁻¹³

q = 4.67 x 10⁻⁷ C

now, number of electron

 N = \dfrac{q}{e}

e is the charge of electron which is equal to 1.6 x 10⁻¹⁹ C

  N = \dfrac{4.67\times 10^{-7}}{1.6\times 10^{-19}}

       N = 2.92 x 10¹² electrons

electrons were transferred from one ball to the other is 2.92 x 10¹²

5 0
3 years ago
Can someone help me with this please...It's Earth Space Science
Andrew [12]
Your answer is correct: Resident 4 would provide the scientist with the most valid results.
3 0
3 years ago
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