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3 years ago

1. Adrian has a rectangular block with the dimensions 3.5 in by 8.0 in by 5.5

Chemistry

1 answer:

miskamm [114]3 years ago

8 0

Answer:

The density of the block is 2.827 grams/ cubic inch

Explanation:

The density of the block can be obtained by dividing the given mass of the block by its volume.

Density = mass / volume

The mass of the block given is 435.5 grams

The volume of the block can be obtained by using the formula:

Volume = Length X breadth X height

Volume = 3.5 X 8 X 5.5 = 154 $in^3$

There fore the density will be 435.5 / 154 = 2.827 grams/ cubic inch

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That's why it's important for you to use water wisely and not to waste it. When you waste water, you're taking water that other people might need. But when you use water carefully, you leave more water for other people to use. It is also important to use water carefully because our weather can be unpredictable.

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2 years ago

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If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water

djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of water will increase

$\Delta T=3.32 C^{0}$

Explanation:

$q = mC\Delta T$

Here , q = heat added / removed from the substance

m = mass of the substance taken

$\Delta T$ = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

$4.18 J/gC^{0}$

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

$q = mC\Delta T$

on transposing ,

$\Delta T=\frac{q}{mC}$

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3 0

3 years ago

How old is a bone if it now .3125 of C-14 when it originally had 80.0g of C-14

Taya2010 [7]

<h3>Answer:</h3>

42960 years

<h3>Explanation:</h3>

<u>We are given;</u>

Remaining mass of C-14 in a bone is 0.3125 g
Original mass of C-14 on the bone is 80.0 g
Half life of C-14 is 5370 years

We are required to determine the age of the bone;

Using the formula;

Remaining mass = Original mass × 0.5^n , where n is the number of half lives.

Therefore;

0.3125 g = 80.0 g × 0.5^n

3.90625 × 10^-3 = 0.5^n

Introducing logarithm on both sides;

log 3.90625 × 10^-3 = n log 0.5

Solving for n

n = log 3.90625 × 10^-3 ÷ log 0.5

= 8

Therefore, the number of half lives is 8
But, 1 half life is 5370 years
Therefore;

Age of the rock = 5370 years × 8

= 42960 years

Thus, the bone is 42960 years old

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3 years ago

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vekshin1

Answer:

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