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2 years ago

How does the amount of atmosphere affect what color the sky appears to be?

1 answer:

3 0

The atmosphere creates a cover over the earth preventing us from seeing space and it’s natural color and the light that is created by the sun reflected on the ocean creates the color that the sky appears to be blue

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The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge

lesya [120]

Answer:

Loss, $\Delta E=-10.63\ J$

Explanation:

Given that,

Mass of particle 1, $m_1=m =0.66\ kg$

Mass of particle 2, $m_2=7.4m =4.884\ kg$

Speed of particle 1, $v_1=2v_o=2\times 6=12\ m/s$

Speed of particle 2, $v_2=v_o=6\ m/s$

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

$m_1v_1+m_2v_2=(m_1+m_2)V$

$V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}$

$V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}$

V = 6.71 m/s

Initial kinetic energy before the collision,

$K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)$

$K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)$

$K_i=135.43\ J$

Final kinetic energy after the collision,

$K_f=\dfrac{1}{2}(m_1+m_2)V^2$

$K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2$

$K_f=124.80\ J$

Lost in kinetic energy,

$\Delta K=K_f-K_i$

$\Delta K=124.80-135.43$

$\Delta E=-10.63\ J$

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

7 0

2 years ago

How does newtons law of the universal gravitation help scientist describe the universe

Afina-wow [57]

You need to know everything is made of atoms they are always colliding and they are never still because you'd think that every thing in space is still all the time even if it's not making visibly

5 0

2 years ago

Read 2 more answers

The velocity vector of an object with a centripetal acceleration is never tangent to the circular path.

Veseljchak [2.6K]

<em>The velocity vector of an object with a centripetal acceleration is never tangent to the circular path is False.</em>

Answer: <em>False</em>

Explanation:

Centripetal acceleration is a feature of objects in uniform circular motion. In that case velocity is along the tangent drawn to the circular path. For an object to be called accelerating its velocity should be variable but speed needn’t.

Even when the speed is constant an object can be accelerating. The direction of velocity of an object in uniform circular motion keeps changing continuously. This change in velocity in uniform circular motion is equal to the centripetal acceleration.

5 0

2 years ago

Two objects of mass 6 kg and 3 kg respectively move at a constant speed of 5m/s in a straight line. When an equal external force

Ivanshal [37]

A is the correct answer

8 0

2 years ago

What is a work done on a body moving in a circular path

lesantik [10]

Zero

This is because, when a body moves in a circular path, then the centripetal force acts along the radius of the circle, and it is at right angles to the motion of the body.

4 0

2 years ago