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trasher [3.6K]
3 years ago
8

Calculate the density of gold if 96500kg mass of gold is adjusted in the volume of 5m cube​

Physics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

96500÷5=19300

Explanation:

96500÷5=19300

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In 1939 or 1940, Emanuel Zacchini took his human-cannonball act to an extreme. After being shot from a cannon, he soared over th
Arlecino [84]
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v_y=26.5 sin(53)=21.163v_x=26.5 cos(53)=15.948 
then

let x=0since you are going to land on a 3m tally=-.5(9.8)t^2+ 21.163*t
y=0=-4.9t+21.163t=4.31
vx*4.31= total distance travelled=68.88m
Then for the first wheel, you have 15.948m=vxdetermine the time when he reaches 23 meters, that is

23/15.948=1.44218 sec

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h(1.44218)=20.329

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using the time value of the vertex, determine horizontal distance travelled
34.438m away from cannon
8 0
2 years ago
At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi
Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36.  Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and \mu be the friction coefficient and m be the mass of car.

Hence, the given data is as follows.

                v = 0,     s = 84 m,     \mu = 0.36

According to Newton's law of second motion the expression for acceleration is as follows.

                      F = ma

                 -\mu N = ma

                 -\mu mg = ma

                      a = -\mu g

Also,    

               v^{2} = u^{2} + 2as

              (0)^{2} = u^{2} + 2(-\mu g)s

                  u^{2} = 2(\mu g)s

                            = \sqrt{2(0.36)(9.81 m/s^{2})(84 m)}

                            = 24.36 m/s

Thus, we can conclude that the speed of the car when the driver slammed on (and locked) the brakes is 24.36 m/s.

4 0
3 years ago
Rob is studying for an exam. He listed some properties of magnets in a Maglev train.
fredd [130]
The answer is the third one. Maglev is short for Magnetic Levitation in which trains skim on a guideway utilizing the guideline of attractive shock. Every magnet has two shafts. Presently in the event that you play with two magnets, you'll understand that inverse shafts pull in, though comparable posts repulse. This shocking property of magnets is utilized as a part of Maglev trains. However,instead of utilizing lasting magnets, the standard of electromagnetism is utilized to make solid and huge impermanent magnets. At the point when an electric current is gone through a loop of wire, attractive field is created around the curl as indicated by Faraday's laws.
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3 years ago
Read 2 more answers
During long jump athlete runs before taking the jump by doing so he
Alenkasestr [34]

A. During long jump athlete runs before taking the jump by doing so he provides himself a larger inertia.

<h3>What is inertia?</h3>

Inertia is the reluctance of an object to stop moving once in motion or start moving when it is at rest.

When an athlete runs before taking the jump, he is trying to increase his inertia, that is his reluctance to stop, thereby increasing his forward motion or jump.

Thus, during long jump athlete runs before taking the jump by doing so he provides himself a larger inertia.

Learn more about inertia here: brainly.com/question/1140505

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5 0
1 year ago
A 524-Hz longitudinal wave in air has a speed of 345 m/s. (a) What is the wavelength? (b) How much time is required for the phas
zhuklara [117]

Answer: a) 152 cm

b) 0.725 ms

c) 10°

Explanation:

Given

Frequency of the wave, f = 524 Hz

Speed of the wave, v = 345 m/s

Wavelength of the wave, λ = ?

The relation for wavelength is given by

λ = f/v, on substituting

λ = 524 / 345

λ = 1.52 m or 152 cm

T = 1/v

T = 0.0029 s

T = 2.9 ms.

Note that the phase change is 90°, thus the time required to change the phase by 90° is

t = 2.9 * (90 / 360)

t = 2.9 * 0.25

t = 0.725 ms

The phase difference at a particular instance 4.4 cm apart is

= (4.4 / 152) * 360

= 0.02895 * 360

= 10.422°

a) 152 cm

b) 0.725 ms

c) 10°

5 0
3 years ago
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