Answer:
Mass = 473.2 g
Explanation:
Given data:
Mass of cobalt(III) nitrate = 206 g
Mass of silver bromide produced = ?
Solution:
Chemical equation:
CoBr₃ + 3AgNO₃ → 3AgBr + Co(NO₃)₃
Number of moles of cobalt(III) nitrate:
Number of moles = mass/ molar mass
Number of moles = 206 g/ 245 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of cobalt(III) nitrate with silver bromide.
Co(NO₃)₃ : AgBr
1 : 3
0.84 : 3/1 × 0.84 = 2.52 mol
Mass of silver bromide:
Mass = number of moles × molar mass
Mass = 2.52 mol × 187.77 g/mol
Mass = 473.2 g
The answer is true the si base unit for mass is the gram
Answer:
6.098M
Explanation:
akording to m1v1/m2v2=n1/n2