Question

The view factor for radiation emitted by surface 1 to surface 2 was calculated to be 0.4. The working area of surface 1 is 0.01 m2, the working area of surface 2 is 0.04 m2. What is the view factor for radiation emitted by surface 2 to surface 1?

Answer 1

Answer:

The view factor for radiation emitted by surface 2 to surface 1 is 0.1

Explanation:

Given

$F_{12} = 0.4$

$A_1 = 0.01m^2$

$A_2 = 0.04m^2$

Required

Determine $F_{21}$

To do this, we make use of the following equivalent ratio

$A_1 * F_{12} = A_2 * F_{21}$

Make $F_{21$ the subject

$F_{21} = \frac{A_1 * F_{12}}{ A_2}$

Substitute values into the equation

$F_{21} = \frac{0.01m^2 * 0.4}{0.04m^2}$

$F_{21} = \frac{0.01 * 0.4}{0.04}$

$F_{21} = \frac{0.004}{0.04}$

$F_{21} = 0.1$