Answer:
891 excess electrons must be present on each sphere
Explanation:
One Charge = q1 = q
Force = F = 4.57*10^-21 N
Other charge = q2 =q
Distance = r = 20 cm = 0.2 m
permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)
Using Coulomb's law,
F=[1/4pieo]q1q2/r^2
F = [1/4pieo]q^2 / r^2
q^2 =F [4pieo]r^2
q = r*sq rt F[4pieo]
q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]
q = 1.42614*10^ -16 C
number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19
n =891
891 excess electrons must be present on each sphere
Answer:
A) First we need to decompose the vector A in x-axis and y-axis:
And also we have for vector B:
To find A + B:
B)
Answer:
23.99N
Explanation:
Given:
Pressure created by the heart = 120mm of hg
converting the pressure into the standard unit of N/m²
1mm of hg =
now, 120 mm of hg in N/m² will be
120mm of hg =
also
given effective area = 15.0 cm² = 15 × 10⁻⁴m²
Now,
Force = Pressure × Area
thus,
Force exerted will be = × 15 × 10⁻⁴m²
or
Force exerted will be = 23.99N
Graph paper can be effectively used to measure the area of irregular objects...... because the graph consists of small units of 1 into 1 cm.. if an irregular object is kept And drawn over the graph then you can consider those 1 into 1 unit boxes for calculating the surface area. moreover find the thickness of the object then we can find the volume too
I think its x-rays if i remember correctly