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Sunny_sXe [5.5K]
3 years ago
10

Which of the following is an illuminated object? a lightbulb a fire the Sun the Moon

Physics
2 answers:
Harlamova29_29 [7]3 years ago
7 0
The lightbulb, the fire, and the Sun all create light from some energy source.

The Moon doesn't create light.  The parts of it that the Sun shines on
are visible, the parts of it that the Sun doesn't shine on are not visible. 

Just like a rock on the ground at night, the Moon must be illuminated
by a flashlight in order to be seen.  The Sun is the flashlight.
Neporo4naja [7]3 years ago
5 0

Answer:

LIGHTBULB

Explanation:

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You have 1.2kg of (AU)gold (that's quite a bit of money at $1839/ounce). Using a heat source you apply 3096 J to the gold and re
melamori03 [73]

Answer:

129 J/Kg°C

Explanation:

Given :

Mass of gold, m = 1.2kg

Quantity of heat applied, Q = 3096 J

Temperature, t2 = 40°C

Temperature, t1 = 20°C

Change in temperature, dt = (40-20)°C = 20°C

Using the relation :

Q = mcdt

Where, C = specific heat capacity of gold

3096 = 1.2kg * C * 20°C

3096 J = 24kg°C * C

C = 3096 J / 24 kg°C

C = 129 J/Kg°C

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3 years ago
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Increases then decreases
4 0
4 years ago
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Heat is transferred from molecules with more kinetic energy to molecules with _________kinetic energy.
Karolina [17]

Answer:

low

Explanation:

the higher the kinetic energy, the More the vibration of molecules, thus heat is more on the side with highly vibrating molecules

3 0
3 years ago
1. when a homemade oil and vinegar salad dressing is left standing, it separates into layers. the salad dressing is a? solution,
salantis [7]
<span>The salad dressing is known as a compound dressing. A compound is simply a combination, or mixture, of two or more ingrediants.
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5 0
3 years ago
A 1.5m long string weighs 0.0020 kg. It is tensioned to 100N. A disturbance travels along it with a wavelength of 1.5m, find:a)
Zigmanuir [339]

Answer:

the propagation velocity of the wave is 274.2 m/s

Explanation:

Given;

length of the string, L = 1.5 m

mass of the string, m = 0.002 kg

Tension of the string, T = 100 N

wavelength, λ = 1.5 m

The propagation velocity of the wave is calculated as;

v = \sqrt{\frac{T}{\mu} } \\\\\mu \ is \ mass \ per \ unit \ length \ of \ the \ string\\\\\mu = \frac{0.002 \ kg}{1.5 \ m} = 0.00133 \ kg/m\\\\v = \sqrt{\frac{100}{0.00133} } \\\\v = 274.2 \ m/s

Therefore, the propagation velocity of the wave is 274.2 m/s

7 0
3 years ago
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