Answer:
A=16+j12…'B=6+j10.4
Explanation:
add the following vector given in
Answer:
I = 1205.69 Lx
Explanation:
The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀
I = I₀ sin θ
in this case with the initial data we can calculate the initial irradiance
I₀ =
I₀ = 1600 /sin 53
I₀ = 2003.42 lx
for when the angle is θ = 37º
I = 2003.42 sin 37
I = 1205.69 Lx
Answer:
screw is the answer of the question
Explanation:
The end-use industries of thermochromic materials include packaging, printing & coating, medical, textile, industrial, and others. Printing & coating is the fastest-growing end-use industry of thermochromic materials owing to a significant increase in the demand for thermal paper for POS systems. The use of thermochromic materials is gaining momentum for interactive packaging that encourages consumers to take a product off the shelf and use it.
Answer:
576.21kJ
Explanation:
#We know that:
The balance mass ![m_{in}+m_{out}=\bigtriangleup m_{system}](https://tex.z-dn.net/?f=m_%7Bin%7D%2Bm_%7Bout%7D%3D%5Cbigtriangleup%20m_%7Bsystem%7D)
so, ![m_e=m_1-m_2](https://tex.z-dn.net/?f=m_e%3Dm_1-m_2)
![Energy \ Balance\\E_{in}-E_{out}=\bigtriangleup E_{system}\\\\\therefore Q_i_n+m_eh_e=m_2u_2-m_1u_1](https://tex.z-dn.net/?f=Energy%20%5C%20Balance%5C%5CE_%7Bin%7D-E_%7Bout%7D%3D%5Cbigtriangleup%20E_%7Bsystem%7D%5C%5C%5C%5C%5Ctherefore%20Q_i_n%2Bm_eh_e%3Dm_2u_2-m_1u_1)
#Also, given the properties of water as;
![(P_1=2Mpa,T_1=300\textdegree C)->v_1=0.12551m^3/kg,u_1=2773.2kJ/kg->h_1=3024.2kJ/kg\\\\(P_2=2Mpa,T_1=500\textdegree C)->v_2=0.17568m^3/kg,u_1=3116.9kJ/kg->h_1=3468.3kJ/kg](https://tex.z-dn.net/?f=%28P_1%3D2Mpa%2CT_1%3D300%5Ctextdegree%20C%29-%3Ev_1%3D0.12551m%5E3%2Fkg%2Cu_1%3D2773.2kJ%2Fkg-%3Eh_1%3D3024.2kJ%2Fkg%5C%5C%5C%5C%28P_2%3D2Mpa%2CT_1%3D500%5Ctextdegree%20C%29-%3Ev_2%3D0.17568m%5E3%2Fkg%2Cu_1%3D3116.9kJ%2Fkg-%3Eh_1%3D3468.3kJ%2Fkg)
#We assume constant properties for the steam at average temperatures:![h_e=\approx(h_1+h_2)/2](https://tex.z-dn.net/?f=h_e%3D%5Capprox%28h_1%2Bh_2%29%2F2)
#Replace known values in the equation above;![h_e=(3024.2+3468.3)/2=3246.25kJ/kg\\\\m_1=V_1/v_1=0.19m^3/(0.12551m^3/kg)=1.5138kg\\\\m_2=V_2/v_2=0.19m^3/(0.17568m^3/kg)=1.0815kg](https://tex.z-dn.net/?f=h_e%3D%283024.2%2B3468.3%29%2F2%3D3246.25kJ%2Fkg%5C%5C%5C%5Cm_1%3DV_1%2Fv_1%3D0.19m%5E3%2F%280.12551m%5E3%2Fkg%29%3D1.5138kg%5C%5C%5C%5Cm_2%3DV_2%2Fv_2%3D0.19m%5E3%2F%280.17568m%5E3%2Fkg%29%3D1.0815kg)
#Using the mass and energy balance relations;
![m_e=m_1-m_2\\\\m_e=1.5138-1.0815\\\\m_e=0.4323kg](https://tex.z-dn.net/?f=m_e%3Dm_1-m_2%5C%5C%5C%5Cm_e%3D1.5138-1.0815%5C%5C%5C%5Cm_e%3D0.4323kg)
#We have
: we replace the known values in the equation as;
![Q_i_n+m_eh_e=m_2u_2-m_1u_1\\\\Q_i_n=0.4323kg\times3246.2kJ/kg+1.0815kg\times3116.9-1.5138kg\times2773.2kJ/kg\\\\Q_i_n=573.21kJ](https://tex.z-dn.net/?f=Q_i_n%2Bm_eh_e%3Dm_2u_2-m_1u_1%5C%5C%5C%5CQ_i_n%3D0.4323kg%5Ctimes3246.2kJ%2Fkg%2B1.0815kg%5Ctimes3116.9-1.5138kg%5Ctimes2773.2kJ%2Fkg%5C%5C%5C%5CQ_i_n%3D573.21kJ)
#Hence,the amount of heat transferred when the steam temperature reaches 500°C is 576.21kJ