All categories

3 years ago

What do Engineering Systems achieve?

Engineering

1 answer:

sladkih [1.3K]3 years ago

3 0

Answer:

Systems Engineering helps avoid omissions and invalid assumptions, helps to manage real world changing issues, and produce the most efficient, economic and robust solution.

Explanation:

You might be interested in

A Capacitor is a circuit component that stores energy and can be charged when current flows through it. A current of 2A flows th

valkas [14]

Answer:

6uC

Explanation:

View Image

Derive an equation for charge(q) in term of current then solve:

$q(t)=\int\limits^\tau_{\tau_0} {i(t)} \, d\tau+q_0$

Use the equation above to solve for your net charge.

6 0

3 years ago

/ Air enters a 20-cm-diameter 12-m-long underwater duct at 50°C and 1 atm at a

Digiron [165]

Answer:

A) EXIT TEMPERATURE = 14⁰C

b) rate of heat transfer of air = - 13475.78 = - 13.5 kw

Explanation:

Given data :

diameter of duct = 20-cm = 0.2 m

length of duct = 12-m

temperature of air at inlet= 50⁰c

pressure = 1 atm

mean velocity = 7 m/s

average heat transfer coefficient = 85 w/m^2⁰c

water temperature = 5⁰c

surface temperature ( Ts) = 5⁰c

properties of air at 50⁰c and at 1 atm

= 1.092 kg/m^3

Cp = 1007 j/kg⁰c

k = 0.02735 W/m⁰c

Pr = 0.7228

v = 1.798 * 10^-5 m^2/s

determine the exit temperature of air and the rate of heat transfer

attached below is the detailed solution

Calculate the mass flow rate

= p*Ac*Vmean

= 1.092 * 0.0314 * 7 = 0.24 kg/s

4 0

3 years ago

You want to improve your grades so that you make all A's next 6 weeks. List examples of quantitative and qualitative data you sh

Naddika [18.5K]

Explanation:

z3d33sxurljt 36f

3fभथठभदाफमदखज्ञफादफज्ञादफज्ञिलफ इऋबिअऋब

6 0

3 years ago

Poles are values of Laplace transform variable, s, that make denominator of transfer function zero. Zeros are values of Laplace

Ostrovityanka [42]

Answer:

Zero 1 = -1

Zero 2 = -3

Pole 1 = 0

Pole 2 = -2

Pole 3 = -4

Pole 4 = -6

Gain = 4

Explanation:

For any given transfer function, the general form is given as

T.F = k [N(s)] ÷ [D(s)]

where k = gain of the transfer function

N(s) is the numerator polynomial of the transfer function whose roots are the zeros of the transfer function.

D(s) is the denominator polynomial of the transfer function whose roots are the poles of the transfer function.

k [N(s)] = 4s² + 16s + 12 = 4[s² + 4s + 3]

it is evident that

Gain = k = 4

N(s) = (s² + 4s + 3) = (s² + s + 3s + 3)

= s(s + 1) + 3 (s + 1) = (s + 1)(s + 3)

The zeros are -1 and -3

D(s) = s⁴ + 12s³ + 44s² + 48s

= s(s³ + 12s² + 44s + 48)

= s(s + 2)(s + 4)(s + 6)

The roots are then, 0, -2, -4 and -6.

Hope this Helps!!!

3 0

4 years ago

Explain why a hydraulic power system would be the best choice when building a device or vehicle that requires large amounts of p

ohaa [14]

Answer:because it faster

Explanation: and when building a device or vehicle that requires large

3 0

3 years ago