Carbon Dioxide + Oxygen Gas + Water + Sunlight Yields Glucose + Oxygen
Answer:
A. 96.3 mg/dL
Absolute error: 5.7 mg/dL
Relative error: 5.6%
B. 97.2 mg/dL
Absolute error: 4.8 mg/dL
Relative error: 4.7%
C. 104.8 mg/dL
Absolute error: 2.8 mg/dL
Relative error: 2.7%
D. 111.5 mg/dL
Absolute error: 9.5 mg/dL
Relative error: 9.3%
E. 110.5 mg/dL
Absolute error: 8.5 mg/dL
Relative error: 8.3%
Explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
In your exercise, we have that
Actual Value = 102.0 mg/dL
A. 96.3 mg/dL:
B. 97.2 mg/dL
C. 104.8 mg/dL
D. 111.5 mg/dL
E. 110.5 mg/dL
Answer:
Across a period, effective nuclear charge increases as electron shielding remains constant. A higher effective nuclear charge causes greater attractions to the electrons, pulling the electron cloud closer to the nucleus which results in a smaller atomic radius. ... This results in a larger atomic radius.
Explanation:
Now lets d8
Answer:
pOH = 4.8
pH = 9.2
Explanation:
Given data:
Hydrogen ion concentration = 6.3×10⁻¹⁰M
pH of solution = ?
pOH of solution = ?
Solution:
Formula:
pH = -log [H⁺]
[H⁺] = Hydrogen ion concentration
We will put the values in formula to calculate the pH.
pH = -log [6.3×10⁻¹⁰]
pH = 9.2
To calculate the pOH:
pH + pOH = 14
We will rearrange this equation.
pOH = 14 - pH
now we will put the values of pH.
pOH = 14 - 9.2
pOH = 4.8
