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Aleksandr [31]
3 years ago
8

Add coefficients to balance the equation to make water. H2(g) +O2 (g)H20 (1)

Chemistry
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

2H2+2O2=2H2O

Explanation:

hope this helps

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You have to be romantic with her and give her presents and always say that she is right.
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3 years ago
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4. How would you calculate the poH of a base when given the<br><br> concentration of [OH]-?
Novay_Z [31]

Answer:

Use pOH = -log₁₀ [OH-]

Explanation:

pOH can be calculated from the concentration of hydroxide ions using the formular below:

pOH = -log₁₀ [OH-]

The pOH is the negative logarithm of the hydroxide ion concentration.

3 0
3 years ago
What is the molarity of a 2.0 liter solution containing 58 grams of nacl?
Savatey [412]
First, need to know the formula of Molarity. 
                     moles of solute
  Molarity = ---------------------------
                      liters of solution

Given 
    2.0 liter of solution 
    58 grams of NaCl

Base of my research the moles of 58 grams of NaCl is 0.750 moles

Solution

                    0.750 moles
Molarity = -----------------------              = 0.375
                             2.0 L

The molarity of this solution is 0.375 
 
4 0
3 years ago
How does the strength of a liquid’s intermolecular forces affect its viscosity
igor_vitrenko [27]

Answer:

Viscosity increases with stronger intermolecular forces

Step-by-step explanation:

<em>Viscosity</em> is the resistance of a liquid to flow.

A liquid can flow easily only if the molecules can move past each other with little resistance.

If there are strong intermolecular attractive forces among molecules, it is more difficult for them to move past each other.

For example, the molecules in molasses have strong attractive forces, so it is quite viscous.

8 0
3 years ago
In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flig
drek231 [11]

Answer:

27,397.23 L would be needed for a successful trip.

Explanation:

The problem gives us <u>the density (ρ) of the fuel,</u> by telling us that there are 803 g of fuel in 1 L, in which case:

ρ=\frac{mass}{Volume}=\frac{803g}{1L}  =803\frac{g}{L}

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg * \frac{1000g}{1kg} = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:

803 g/L = \frac{2.2*10^{7}g }{V} \\V=\frac{2.2*10^{7}g }{803g/L}\\ V=27397.26 L

Thus 27,397.23 L would be needed for a successful trip.

5 0
3 years ago
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