Answer:
Explanation:
The major difference between pure and applied chemistry is the purpose and intent of the study.
Pure chemistry deals with the study of matter, matter transformations, and interactions between the different materials of the world, for only the sake of gaining empirical knowledge about the various substances that exist in the world. It does not really seek to apply this knowledge to do anything industrial.
Applied chemistry is the study of chemistry with the aim of utilizing this knowledge to solve the various problems that man faces. This approach of study is not for knowledge sake alone, rather it is for industrial application
Answer:
Explanation:
<u>According to Arrhenius concept of acid and base:</u>
"When a base in a solution, produces/yields OH- (Hydroxide) ions."
So, when a base is dissolved in a solution, it produces OH- ions.
<u>For example:</u>
NaOH ⇄ Na⁺ + OH⁻ (So, it is a base)
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Hope this helped!
<h3>~AH1807</h3>
The Answer is A CH2O
The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.
Answer: The law of conservation of mass states that mass is neither created or destroyed, so the combined mass of all the products after the reaction will be the same as the mass of all the reactants and never more, but since the flask is not closed, the gases produced from the reaction will move into the atmosphere and the product left behind , the solids and/or liquids, will be the only products that you’ll end up weighing, meaning it’ll be less weight than the original reactants. The reason I’m interchanging weight and mass is because although weight changes with gravity, so long as the gravitational force stays constant throughout the experiment, it’s pretty much the same.
Explanation:
Answer:
Explanation:
Hello.
In this problem we must realize that there is heat flow that moves from the hot metal object and the hot water to the cold water and the cold aluminum cup, which allows us to write:
Which means that the heat lost be the hot metal object and the hot water is gained by both the cold water and the cold aluminum cup, which can be written in terms of mass, specific heats and change in temperature towards the equilibrium temperature (35.9 °C):
We need to solve for the specific heat of the metal as shown below:
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