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2 years ago

I need help pls its due tomorrow i wanna get the answer right pls.

Chemistry

1 answer:

marin [14]2 years ago

6 0

Answer:

1) Without our atmosphere we wouldn't have life! The atmosphere protects our earth from letting harmful substances or rocks into our planet, which could cause damage.

2) You interact with the atmosphere in both good ways and bad. You interact by putting up things like flowers and trees, but in bad ways by releasing bad things (like carbon dioxide) and by light pollution!

3) The factors that can affect climate of an area, by latitude and longitude!

Explanation:

Hope this helps! Plz mark as brainliest! :)

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What mass of compound must be weighed out to have a 0.0223 mol sample of H2C2O4 (M=90.04 g/mol)?

rodikova [14]

Mass of H2C2O4 :

mm = 90.04 g/mol

number of moles : 0.0223 moles

m = n * mm

m = 0.0223 * 90.04

m = 2.007 g

hope this helps!.

5 0

3 years ago

Why does burned toast taste so bad? Is it a chemical or physical change?

german

Because things that are burnt have been changed into something else like moldy bread thats cooked.

It is chemical change because you cannot unburn something.

4 0

2 years ago

Read 2 more answers

Caed for this question.

OLga [1]

Answer:

0.962 atm.

97.4 kPa.

731 torr.

14.1 psi.

97,434.6 Pa.

Explanation:

Hello.

In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

$p=731mmHg*\frac{1atm}{760mmHg} =0.962atm$

- Kilopascals:: 101.3 kPa = 760 mmHg:

$p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa$

- Torrs: 760 torr = 760 mmHg:

$p=731mmHg*\frac{760 torr}{760mmHg} =731 torr$

- Pounds per square inch: 14.69 psi = 760 mmHg:

$p=731mmHg*\frac{14.69}{760mmHg} =14.1psi$

- Pascals: 101300 Pa = 760 mmHg:

$p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa$

Best regards.

5 0

2 years ago

What is the ph of a solution that has a poh of 11.24

galina1969 [7]

Always remember that pH + pOH = 14
Here, you have a pOH of 11.24, so you replace it in the equation, and u get:
pH + 11.24 = 14

Then, You move 11.24 to the other part. and moving from a part to another change the sign of the equation. And you get:
pH = 14 - 11.24 = 2.76

So, the pH of a solution that has a pOH of 11.24 is pH = 2.76

Hope this Helps :)

7 0

3 years ago

EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK

mihalych1998 [28]

Answer:

Check the explanation

Explanation:

When,

pH = -log[H+] = 3.30

[H+] = $5.0 X 10^{-4} M$

$Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^{-11}$

$alpha[Y^-4] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6$

= $1.56 X 10^{-20} + 3.12 X 10^{-17} + 2 X 10^{-15} + 4 X 10^{-14} + 1.6 X 10^{-13} + 2.34 X 10^{-16} + 2 X 10^{-23}$

= $2.02 X 10^{-13}$

When,

pH = -log[H+] = 10.15

[H+] = $7.08 X 10^{-11} M$

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = $7.4 X 10^{-7}$ ; Ka6 = $4.3 X 10^-11$

$alpha[Y^{-4}] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6$

= $1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}$

= $5.12 X 10^{-23}$

4 0

3 years ago